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svlad2 [7]
4 years ago
12

A researcher is studying the effect of ten different variables on a critical measure of business performance. In selecting the b

est set of independent variables to predict the dependent variable, a forward selection method is used. How are variables selected for inclusion in the model?
A. Smallest p-value

B. Highest increase in the multiple r-squared

C. smallest coefficient

D. Largest p-value
Mathematics
2 answers:
Romashka-Z-Leto [24]4 years ago
7 0

Answer:

B. Highest increase in the multiple r-squared

Step-by-step explanation:

Forward selection is a type of stepwise regression which begins with an empty model and adds in variables one by one. In each forward step, you add the one variable that gives the single best improvement to your model.

We know that when more variables are added, r-squared values typically increase with probability 1. Based on this and the above definition, we select the candidate variable that increases r-Squared the most and stop adding variables when none of the remaining variables are significant.

Tasya [4]4 years ago
5 0

Answer:

D. Largest p-value

Step-by-step explanation:

P-value assists statistician to know the importance of their result. It assists them in determining the strength of their evidence.

A large P-value which is less than 0.05 depicts that an evidence is week against null hypothesis, therefore the null hypothesis must be accepted.

A small P-value <0.05 depicts a strong evidence against null hypothesis, so the null hypothesis must be rejected.

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An object is traveling at a steady speed of 10 and one tenth km​/h. How long will it take the object to travel 4 and nine tenths
My name is Ann [436]

Answer:

Estimated Answer=\frac{1}{2} hour

Exact Answer= \frac{49}{101} hr

Step-by-step explanation:

Steady speed of the object =10 and one tenth km​/h = 10\frac{1}{10} km/hr

Distance to be Covered=4 and nine tenths km =4\frac{9}{10} km

To the nearest integer,

Steady speed of the object = 10 km/hr

Distance=5km

Time Taken = \frac{Distance}{Average Speed}

==\frac{5}{10} =\frac{1}{2} hr

The estimated answer is 1/2 hr.

Next, we determine the exact answer.

Time Taken = \frac{Distance}{Average Speed}\\  = 4\frac{9}{10} \div 10\frac{1}{10}\\=\frac{49}{10} \div \frac{101}{10}\\=\frac{49}{10} X \frac{10}{101}\\=\frac{49}{101} hr

The exact time taken is \frac{49}{101} hr

3 0
3 years ago
PLEASE ANSWER!!!!!!
Contact [7]

Answer:

The answer is D

Step-by-step explanation:

the first one is equal to the equation 4 < 3 because of absolute value, second 4 < 3, third 3 < -4, fourth -3 < 4

7 0
3 years ago
Read 2 more answers
When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

7 0
4 years ago
one angle of a linear pair is 10 more than two thirds the other angle. find the measure if both angles
BigorU [14]

Answer:

One Angle = 110°

Other Angle = 70°

Step-by-step explanation:

A linear pair means that two angles are in a straight line (or, a straight angle).

A straight line is 180 degrees.

THey are supplementary.

We can say one angle is "a" and another one is "b".

<em>One angle is 10 MORE THAN 2/3rds of the other, we can write:</em>

<em>a=\frac{2}{3}b+10</em>

<em />

<em>Also, since they are supplementary (add up to 180), we can write:</em>

<em>a + b = 180</em>

<em />

We can now substitute 1st equation in this one and find b:

a+b=180\\(\frac{2}{3}b+10)+b=180\\\frac{2}{3}b+b=180-10\\\frac{5}{3}b=170\\b=\frac{170}{\frac{5}{3}}\\b=170*\frac{3}{5}\\b=110

Since a + b = 180, we can write:

a + 110 = 180

so,

a = 180 - 110

a = 70

Thus,

One Angle = 110°

Other Angle = 70°

8 0
3 years ago
Are the ratios 84/105 and 128/160 proportional? Give two different reasons to support your answer.
Karolina [17]

We have been given two ratios and we are supposed to compare our ratios whether they are proportional or not.

1. We will reduce our fractions to compare our ratios. Let us simplify each of our given fractions.

\frac{84}{105}

Let us divide numerator and denominator with greatest common factor. We can see that 21 is GCF of our ratio.

\frac{4}{5}

Now we will simplify our second ratio.

\frac{128}{160}

GCF of our fraction is 32. Upon dividing our fraction by 32 we will get,

\frac{4}{5}

We can see that our both ratios are similar.

2. Now we will find decimal values of our fractions.

\frac{84}{105}=0.8

\frac{128}{160}=0.8

We can see that 0.8=0.8.

Therefore, we can say that our ratios are proportional.

4 0
4 years ago
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