For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3
Answer:
The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
The standard form of a line is in the form

A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:

Subtract 3y from both sides:

Which of course is equivalent to

Which is the standard form, given the coefficients A=1, B=-3, C=6.
Answer:
y=mx+b
Step-by-step explanation:
Answer:
f = 1
Step-by-step explanation:
Use the method of cross- multiplication
=
⇒ ad = bc, thus
20f = 5(f + 3) ← distribute
20f = 5f + 15 ( subtract 5f from both sides )
15f = 15 ( divide both sides by 15 )
f = 1