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natima [27]
3 years ago
14

I WILL GIVE BRAINLIEST a scale on a map shows that 2 inches = 25 miles Part A: How many inches on the map = 60 miles? ----------

-------------------------------------------------------------- Part B: How many miles are represented by 1/4 inch on the map?
Mathematics
1 answer:
bija089 [108]3 years ago
5 0

Answer:

4.8 in, 3.125 mi

Step-by-step explanation:

This situation models direct proportionality, hence, if one variable increases, the other goes increases as well and vice versa. In this case, the variables are inches and miles.

Part A: Since you multiply 60/25 by 25 to get 60 miles, we know that the value in inches will be 2 * 60/25 = 4.8 inches.

Part B: Since you divide 2 by 8 to get 1/4 inches, we know that the value in miles will be 25 / 8 = 3.125 miles.

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Given Info: "The dashed triangle is the image of the solid triangle"

So the "before" is the large solid triangle and the "after" is the smaller dashed triangle.

The horizontal side of the solid triangle is 15 units. The corresponding side for the dashed triangle is 3 units. Dividing the two values gives: 3/15 = 1/5 = 0.2

Make this value negative. The reason why is due to the fact that we have a sort of reflection going on as we're scaling down the figure. 

So the final answer is  -0.2

3 0
3 years ago
During an exit survey after a play, 75 of the first 120 people said they did not like the play.
MA_775_DIABLO [31]
<span>I think its A= 62% and B=37%  and sorry for the answer Brainly asked me</span>
4 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
What is the GCF of 28x3 and 28x5?
Sergio039 [100]

Answer:

28x^3

Step-by-step explanation:

8 0
2 years ago
Erin spent $15.30 on ingredients for cookies she’s making for the school bake sale. How many cookies must she sell at $0.35 a pi
blondinia [14]

Answer:

she needs to sell at least 44 cookies to make a $0.10 profit

Step-by-step explanation:

to find the answer all you have to do is divide 15.30 by 0.35

4 0
3 years ago
Read 2 more answers
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