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Snezhnost [94]
3 years ago
13

The _________ contains approximately 200 million axons.

Computers and Technology
2 answers:
irina1246 [14]3 years ago
6 0
The <span>corpus callosum contains about 200 million axons.</span>
Marrrta [24]3 years ago
5 0

<h2>corpus callosum It is B on edugnuity </h2>
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What phrase best describes the overall structure of the<br> passage
creativ13 [48]

Answer: The one that gives you more vibe that its correct.

Explanation:

3 0
3 years ago
Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file that contains the numbers in
morpeh [17]

Answer:

See explaination

Explanation:

PhoneLookup.java

import java.io.FileReader;

import java.io.IOException;

import java.util.Scanner;

public class PhoneLookup

{

public static void main(String[] args) throws IOException

{

Scanner in = new Scanner(System.in);

System.out.println("Enter the name of the phonebook file: ");

String fileName = in.nextLine();

LookupTable table = new LookupTable();

FileReader reader = new FileReader(fileName);

table.read(new Scanner(reader));

boolean more = true;

while (more)

{

System.out.println("Lookup N)ame, P)hone number, Q)uit?");

String cmd = in.nextLine();

if (cmd.equalsIgnoreCase("Q"))

more = false;

else if (cmd.equalsIgnoreCase("N"))

{

System.out.println("Enter name:");

String n = in.nextLine();

System.out.println("Phone number: " + table.lookup(n));

}

else if (cmd.equalsIgnoreCase("P"))

{

System.out.println("Enter phone number:");

String n = in.nextLine();

System.out.println("Name: " + table.reverseLookup(n));

}

}

}

}

LookupTable.java

import java.util.ArrayList;

import java.util.Collections;

import java.util.Scanner;

/**

A table for lookups and reverse lookups

*/

public class LookupTable

{

private ArrayList<Item> people;

/**

Constructs a LookupTable object.

*/

public LookupTable()

{

people = new ArrayList<Item>();

}

/**

Reads key/value pairs.

atparam in the scanner for reading the input

*/

public void read(Scanner in)

{

while(in.hasNext()){

String name = in.nextLine();

String number = in.nextLine();

people.add(new Item(name, number));

}

}

/**

Looks up an item in the table.

atparam k the key to find

atreturn the value with the given key, or null if no

such item was found.

*/

public String lookup(String k)

{

String output = null;

for(Item item: people){

if(k.equals(item.getName())){

output = item.getNumber();

}

}

return output;

}

/**

Looks up an item in the table.

atparam v the value to find

atreturn the key with the given value, or null if no

such item was found.

*/

public String reverseLookup(String v)

{

String output = null;

for(Item item: people){

if(v.equals(item.getNumber())){

output = item.getName();

}

}

return output;

}

}

Item.java

public class Item {

private String name, number;

public Item(String aName, String aNumber){

name = aName;

number = aNumber;

}

public String getName(){

return name;

}

public String getNumber(){

return number;

}

}

input.txt

Abbott, Amy

408-924-1669

Abeyta, Ric

408-924-2185

Abrams, Arthur

408-924-6120

Abriam-Yago, Kathy

408-924-3159

Accardo, Dan

408-924-2236

Acevedo, Elvira

408-924-5200

Acevedo, Gloria

408-924-6556

Achtenhagen, Stephen

408-924-3522

Note: Replace all the "at" with at symbol

4 0
4 years ago
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
When you print ____, the presentation is printed with one or more slides on each piece of paper?
Artist 52 [7]
When you print handouts, the presentation is printed with one or more slides on each piece of paper. When you print handouts, it's best to have the presentation printed on them for those who can not view the presentation clearly to follow along with. This also serves as a great tool for people who missed the presentation to receive a handout later or for those there to take home and review. 
8 0
3 years ago
A person interested in a career in digital media should have which qualities? Select all that apply.
emmainna [20.7K]
1.Creativity
2.Leadership
3.Attention to detail
5.Enjoyment to learning new things!
6.Vision
No Problem!
5 0
3 years ago
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