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serious [3.7K]
4 years ago
13

Decrease 800 by 40% and give me the answer

Mathematics
1 answer:
Kobotan [32]4 years ago
6 0
Since we are decreasing by 40%

The new value would be 100% - 40% = 60%  of the value

New value =  60% of 800

                   =  (60 / 100) * 800 = 480

Am giving you 480 as the answer.
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A grease gun holds a cylindrical tube of grease that is 14 in. long and has a radius of 1.5 in. With each squeeze, 15 in3 of gre
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3 years ago
Please complete the following
DIA [1.3K]

Answer:

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<em>(</em><em>3</em><em>)</em><em> </em><em>1</em><em>9</em><em>8</em><em> </em><em>metres </em>

b) 2 m/s

Step-by-step explanation:

a) <em>(</em><em>1</em><em>)</em><em> </em>****locate on the graph****

<em>(</em><em>2</em><em>)</em><em> </em>if 2 small squares = 1 second

then (36/2 × 1) = 18 sec

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<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Speed</em><em>=</em><em> </em><em>1</em><em>1</em><em> </em><em>m</em><em>/</em><em>s</em>

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<em> </em>

b) a = change in velocity /change in time

initial velocity = 11 m/s

final velocity. = 28 m/s ***graph***

initial time. = 28 sec ***graph***

final time. = 36 sec ***graph***

a= (11 - 28)/(28/36)

a= (-16/-8)

a= 2 m/s

3 0
3 years ago
A culture started with 5000 bacteria after 5 hours it grew to 6500 bacteria predict how many bacteria will be present after 16 h
postnew [5]

Answer:

After 16 hours bacterial count will be 11600.

Step-by-step explanation:

Bacterial growth is always an exponential growth in a given culture.So the formula for the growth will be

Final counts of bacteria = Initial counts × (rate of growth)^{time}

Given from first part Initial counts = 5000

Final counts= 6500 and time of growth = 5 hours

Then we will get the value of rate of growth of bacteria from the bacteria

⇒ 6500 = 5000×(rate)^{5}

(rate)^{5}= \frac{6500}{5000} = 1.3

Rate = \sqrt[5]{1.3} = 1.05

Now again to get the value of bacteria after 16 hours

Final Count = 5000×(1.05)^{16}

                   = 5000×2.32

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What is the measure of EBG?
Mars2501 [29]

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