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Alenkinab [10]
3 years ago
14

900 is 1/10 of 9000 is correct that expression

Mathematics
1 answer:
belka [17]3 years ago
3 0
Yes since 9000 x 1/10 is 900
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If a suit was on sale for 341 dollars and the price was 38% less that the original price. What the original price
Verizon [17]
$470.58 is the original price
6 0
3 years ago
Read 2 more answers
In each of the following data sets, tell whether the outlier seems certain to be due to an error or whether it could conceivably
emmasim [6.3K]

Answer:

a) There is outlier (lower category), but this outlier seem certain to be due to an error.

b) There is outlier (upper category), this outlier seem certain to be conceivably correct.

Step-by-step explanation:

a) The outlier in the rock weight is certain to be due to an error. As shown, the rock was weighed five time to ascertain the actual weight or perhaps to known the mean weight. <em>Thus, having a value 4.91 can not be true. It can only be due to an error of recording the values.</em> It suppose to be recorded as 49.1.

b) Since this was a sample of annual income of five different families, it quite possible that a particular family annual income is $1, 200, 000. Hence, we cannot regard this outlier an error, rather conceivably true.

See attached for the box plot of the two data sets.

5 0
3 years ago
2 (x + 1) + 6 = 20 - 3x
uysha [10]

Answer:

x=2.4

Step-by-step explanation:

2(x+1)+6=20-3x

We simplify the equation to the form, which is simple to understand  

2(x+1)+6=20-3x

Reorder the terms in parentheses

+(+2x+2)+6=20-3x

Remove unnecessary parentheses

+2x+2+6=+20-3x

We move all terms containing x to the left and all other terms to the right.  

+2x+3x=+20-2-6

We simplify left and right side of the equation.  

+5x=+12

We divide both sides of the equation by 5 to get x.  

x=2.4

(found online but it might help)

3 0
3 years ago
Read 2 more answers
Steve and Karla are studying the text messaging habits of middle school students. They collected data about the number of messag
Bess [88]

Answer:

The correct answer is A.

A) The IQR of Karla's data in 13.

Step-by-step explanation:

The interquartile range can be defined as the difference of upper quartile and lower quartile range. If we want to find the IQR from the box plot, we can simply see the length of the box from the box plot, as it represent the IQR.

We can clearly see that:

IQR of Steve's data is 45 - 31 = 14, hence the second statement is incorrect

IQR of Karla's data is 52 - 39 = 13, hence the first statement is CORRECT

The difference of medians is 43 - 36 = 7

Hence the difference of medians is not the half or twice of IQR ranges of both data sets

5 0
4 years ago
A survey finds that 55 people out of 170 favor increasing property taxes to help pay for a new library. If this data is used to
Aloiza [94]

Answer: B. 0.036

Step-by-step explanation:

Formula for standard error :

SE=\sqrt{\dfrac{p(1-p)}{n}}

, where p = Population proportion and n= sample size.

Let p be the population proportion of the people who favor new taxes.

As per given , we have

n= 170

p=\dfrac{55}{170}\approx0.324

Substitute these values in the formula, we get

SE=\sqrt{\dfrac{0.324(1-0.324)}{170}}\\\\=\sqrt{0.00129}\\\\=0.0359165699921\approx0.036

Hence, the standard error of the estimate is 0.036.

∴ The correct answer is OPTION B. 0.036

8 0
4 years ago
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