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3 years ago

Find the angle between the angle bisectors of a linear pair.

Mathematics

2 answers:

valentinak56 [21]3 years ago

4 0

Answer:

The angle between the angle bisectors of the angles in a linear pair is 90°

Step-by-step explanation:

NISA [10]3 years ago

4 0

Answer:

the angle between bisector and linear is 90. Have a great day

Step-by-step explanation:

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Question 5 You and a friend share a pizza cut into 8 equal slices. Suppose you each eat 3 slices. What

iren2701 [21]

Answer:

3/8

Step-by-step explanation:

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3 years ago

I Calculate each value of angle A to the nearest degree.

Masteriza [31]

Answer: I think the answer is 127 if it is wrong i am so sorry

Don't forget drop a heart.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How many moles are in 2.75 x 10^23 atoms of Sulfur ? please show steps

zimovet [89]

Answer:

2.75x(1023)

=2.75*x*1e+23

=2.7499999999999997e+23*x

=2.7499999999999997e+23x

Step-by-step explanation: Hope this help

5 0

3 years ago

Filbert makes $14 per hour. If he makes time and a half for overtime, how much will he make for working 63 hours?

Marina CMI [18]

Answer:

$1323.00

Step-by-step explanation:

A simple equation that can be used to figure this out is:

p*1.5*o=t

The variables mean:

p- hourly pay

o- hours worked overtime

t- total amount of money earned.

(Also, the 1.5 is always used to calculate overtime, no matter what job, unless otherwise specified, and as referred in the problem as "time and a half").

So, to finally work out this problem:

($14*1.5)*63=?

first, (14*1.5)= $21

($21*63)= $1323.

4 0

3 years ago

The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find

9966 [12]

Answer:

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

Step-by-step explanation:

Step(i):-

Given Differential equation y'' − 5 y' + 4 y = x

Given equation in operator form

D²y - 5 Dy + 4 y = x

⇒ ( D² - 5 D + 4 ) y =x

⇒ f(D) y = Q

where f(D) = D² - 5 D + 4 and Q(x) = x

The auxiliary equation f(m) =0

m²-5 m + 4 =0

m² - 4 m - m + 4 =0

m ( m -4 ) -1 ( m-4) =0

(m - 1) =0 and ( m-4) =0

m = 1 and m =4

The complementary function

$Y_{c} = C_{1} e^{x} + C_{2} e^{4x}$

Step(ii):-

particular integral

Particular integral

$y_{p} = \frac{1}{f(D)} Q(x) = \frac{1}{D^{2} - 5 D + 4} X$

taking common '4'

$= \frac{1}{4(1 + (\frac{D^{2} - 5 D}{4} ))} X$

$=\frac{1}{4} (1 + (\frac{D^{2} -5D}{4})^{-1} )} X$

applying binomial expression

( 1 + x )⁻¹ = 1 - x + x² - x³ +.....

$=\frac{1}{4} (1 - (\frac{D^{2} -5D}{4}) +((\frac{D^{2} -5D}{4})^{2} -...} )X$

Now simplifying and we will use notation D = $\frac{dy}{dx}$

$=\frac{1}{4} (x - (\frac{D^{2} -5D}{4})x +((\frac{D^{2} -5D}{4})^{2}(x) -...}$

Higher degree terms are neglected

$=\frac{1}{4} (x - (\frac{ -5 D}{4}) x)$

The particular integral of given differential equation

$y_{p} = \frac{1}{4} ( x - (\frac{-5}{4} ) (1))$

Final answer:-

General solution of given differential equation

$y = y_{c} + y_{p}$

$Y (x) = C_{1} e^{x} + C_{2} e^{4x} + \frac{1}{4} ( x + (\frac{5}{4} ))$

4 0

3 years ago