If a circle has a radius of 12 and a sector defined by a 7 degree arc , what is the area of a sector
1 answer:
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MO = 12 and PR = 3
Solution:
Given .
Perimeter of ΔMNO = 48
Perimeter of ΔPQR = 12
MO = 12x and PR = x + 2
<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>
Do cross multiplication.
Subtract 48x from both sides.
Divide by 96 on both sides, we get
⇒ 1 = x
⇒ x = 1
Substitute x = 1 in MO an PR.
MO = 12(1) = 12
PR = 1 + 2 = 3
Therefore MO = 12 and PR = 3.
We want to find y from the equation
Multiply each side by (y - 2).
Note that (y-2) in the numerator and denominator cancel out on the left side.
Therefore
3 = 8(y - 2)
3 = 8y - 16
Add 16 to each side.
3 + 16 = 8y - 16 + 16
19 = 8y
Divideach side by 8.
19/8 = y
Answer:
Multiply each side by (y - 2).
Note that (y-2) in the numerator and denominator cancel out on the left side.
Therefore
3 = 8(y - 2)
3 = 8y - 16
Add 16 to each side.
3 + 16 = 8y - 16 + 16
19 = 8y
Divideach side by 8.
19/8 = y
Answer: