Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
Text per day: median= 26
1st quartile= 19
3rd quartile=38
Interquartile=19
Daily attendance: median=357.5
1st quartile=298
3rd quartile=422
Interquartile= 124
Answer:
Probably y=2x+60
Step-by-step explanation:
It seemed to fit best, dont count on my answer tho, not 100% sure :(
When I put the line through the points, the y intercept was around 50/60 and the slope is positive so it eliminated a few answers. then I chose y=2x+60 since that slope seemed more correct than a slop of 8.
Answer:
x^2+12x+36=1+36
Step-by-step explanation:
you divide the 12 by 2 which is 6 and then square it (36)
1128 feet = 1128/5280 miles
it travels at 1128/5280 miles per second
to convert to miles / hour we multiply by 3600
so speed of the bullet = (1128 * 3600) / 5280 = 769.1 mph to nearest tenth.
