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3 years ago

Which is a solution of the system of equations shown?

Mathematics

1 answer:

taurus [48]3 years ago

5 0

Answer:

D. (2, 0)

Step-by-step explanation:

The solutions are the two points of intersection of the graphs:

(-2, -4) and (2, 0)

The latter of these corresponds to choice D, the one you have marked.

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What is the value of the expression f(-3) + 2f(-1) - f (4)<br><br> PLEASE HELP NO LINKS

Bas_tet [7]

Answer:

Step-by-step explanation:

Find f(-3) :

f(x) = x² + 2x for x ≤ -3

That means for those values of x, less than or equal to -3, this is the function.

So, f(-3) = (-3)² + 2(-3) = 9 - 6 = 3

Now, f(-1) :

From the given data, we see it is: f(x) = 2 $(\frac{1}{3} )^{2x}$

We take this because -1 lies between -3 and 4.

Now, f(-1) = 2 $(\frac{1}{3} )^{2(-1)}$

=> $f = (-1) = 2(3)^{2} = 2 (9) = 18$

For f(4) :

Clearly, the function is: $f (x) = \frac{2x - 5}{x-7}$

$f (4) = \frac{2(4)-5}{4-7} = \frac{3}{-3} = -1$

Therefore, <u>f(-3) + f(-1) - f(4) = 3 + 18 - (-1) = 3 + 18 + 1 = 22.</u>

5 0

2 years ago

Help pls and ty :D !!

xxMikexx [17]

Try this suggested option, answers are marked with colour.

4 0

1 year ago

Se desconoce el número de alumnos que hay en una clase de repostería, cada alumno elaborará una galleta para cada compañero una

svetoff [14.1K]

Answer:

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3 years ago

Help please for big points

SOVA2 [1]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

let a,b,c,d be four integers (not necessarily distinct) in the set {1,2,3,4,5}. the no. of polynomials x^4+ax^3+bx^2+cx+d which

Eddi Din [679]

By either long or synthetic division, it's easy to show that

$\dfrac{x^4+ax^3+bx^2+cx+d}{x+1}=x^3+(a-1)x^2+(-a+b+1)x+(a-b+c-1)-\dfrac{a-b+c-d-1}{x+1}$

The quartic will be exactly divisible by $x+1$ when the numerator of the remainder term vanishes, or for those values of $a,b,c,d$ such that

$a-b+c-d-1=0$

I'm not sure how to count the number of solutions (software tells me it should be 80), but hopefully this is a helpful push in the right direction.

8 0

3 years ago