The number that presents 8/9 to the nearest percent is .89.
Same, i need help with geometry too :(
Answer:
Step-by-step explanation:
0.428
(.43)
Okay, here we have this:
Considering the provided information and grades, we are going to calculate the requested GPA, so we obtain the following:
Then we will substitute in the following formula:

Then:

Finally we obtain that the student's GPA for that term is approximately 3.06.
What do you need to solve for?
X=r-4/7-s
S=-r/x+4/x+7
R=-sx+7x+4