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3 years ago

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A group of 5 campers used a total of 12 gallons of water on a camping trip. Each camper used the same amount of water. How many

gallons of water did each campers use?

1 answer:

Gnesinka [82]3 years ago

6 0

(12 gal)/5 = 2.4 gal

Each camper used 2.4 gallons of water.

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Homer and bart plan to buy one computer for 499.00 strictly for gaming purposes. Games cost 49.99 each. define each variable and

ElenaW [278]

499+49.99x=y

499 is the initial cost of the computer

49.99x means you pay 49.99 per game

y is the total cost

3 0

3 years ago

2x - 3y = 8 // <br><br> Find y

konstantin123 [22]

Answer:

$y = -\frac{2}{3} x - \frac{8}{3}$

Step-by-step explanation:

$2x - 3y = 8\\$

Isolate y

$-3y = 8-2x\\-3y = -2x+8$

Divide both sides of the equation by -3

$\frac{-3y}{-3} = \frac{2x}{-3} +\frac{8}{-3} \\\\y = -\frac{2}{3} x - \frac{8}{3}$

7 0

3 years ago

State if the triangles in each pair are similar. If so, state how you know they are similar and complete the similarity statemen

m_a_m_a [10]

<h2>Answer:</h2>

<u>In ΔQRS and ΔQLK</u>,

QR/QL = QS/QK

28/4 = 28/4

7/1 = 7/1 --[1]

<u>AngleLQK and AngleRQS are equal</u> (VOA)

<u>Two sides are in same proportion and the included angle is common (SAS) . Hence both the triangles are similar</u>.

[A] ΔQRS ~ ΔQLK by SAS similarity.

8 0

3 years ago

Read 2 more answers

Weegy 1. jane worked 32 hours in one week. if she worked the same number of hours each day for 4 days, how many hours a day did

rusak2 [61]

Well to get to 32 hours and knowing for all 4 days, she worked the same number of hours.

All we have to do is multiply all these numbers by 4 to see which one is equal to 32.

6 * 4 = 28

10 * 4 = 40

8 * 4 = 32

4 * 4 = 16

c. is the correct answer

6 0

3 years ago

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

so

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0

3 years ago

Read 2 more answers