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motikmotik
3 years ago
14

Ava placed the point of her pencil on the origin of a regular coordinate plane. She marked a point after moving her pencil 4 uni

ts to the left and 7 units up. Which ordered pair identifies where Ava marked her point?

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

\Large{ \boxed{ \bold{ \color{lightgreen}{Solution:}}}}

So, Let's solve this question by using cartesian plane.

  • Here, Origin is shown by (0, 0)
  • Ava moves 4 units left from origin. On the left side of origin, negative x axis begins. So, she reached (-4, 0) now.
  • Then, from that point she moved 7 units upwards. On the upper side, there is positive y axis. So, Finally she will reach point (-4, 7).
  • (-4, 7) is the coordinate of point which is 4 units left from y axis and 7 units up from x axis.
  • It lies on the second quadrant.

Well, What is cartesian plane?

A - A Cartesian coordinate system is a coordinate system that specifies each point uniquely in a plane by a set of numerical coordinates, which are the signed distances to the point from two fixed perpendicular oriented lines, measured in the same unit of length. 

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\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

=\frac{0.216\cdot \:1000}{1000}

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216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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