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Amanda [17]
3 years ago
11

How do you solve E=IR

Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

R = E/I

Step-by-step explanation:

By making R the subject formulas.

E = IR

Divide both sides by I.

E/I = R

R = E/I

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Expand (x-2) (x-1). Must be in polynomial form.
Ludmilka [50]
To expand two terms such as these, we can use the method called FOIL (stands for First, Outer, Inner, Last). Here is what I mean:

We have two terms: (x - 2)(x - 1)

We should first multiply the First two terms of each term in order to complete the F stage:

(x)*(x) = x^{2}

So then, we take the two outer terms and multiply them together to complete the O stage:

(x)*(-1) = -x

So far we have two things that we have calculated; at the end of the FOIL process we will have four.

To keep going with the FOIL, we now multiply the two inner terms to complete the I stage:

(-2)*(x) = -2x

Last but not least, we need to complete the L stage - so we multiply the two last terms of each term:

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Now that we have our four terms, let us add them together and combine like terms:

x^{2}  + (-x) + (-2x) + 2

Since -x and -2x both have the x portion in common and they are added together, we can add them to create one single term:

-x + (-2x) = -3x

So now that we have our terms completed, we can combine into one polynomial equation:

x^{2} + (-3x) + 2 or x^{2} -3x+2
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3 years ago
The graph below shows a system of equations: Draw a line labeled y equals minus x plus 5 by joining the ordered pairs 0, 5 and 5
Nina [5.8K]
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What is the percent of 16/25
Lelechka [254]
16/25 = 0.64 = 64%

Another way to do it is to multiply top and bottom by 4
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Step-by-step explanation:

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The answer is (1+0.18)16.

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