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sp2606 [1]
3 years ago
14

Find the values of x and y for the two intersecting lines.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
4 0
The y value is -1 and the x value is zero
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PLS HURRY ILL GIVE BRAINLIEST<br> Which graph of ordered pairs shows a proportional relationship?
sp2606 [1]

Answer:

pretty sure is the first one

Step-by-step explanation:

a proportional relationship is a straight line that passes through the origin

8 0
3 years ago
Read 2 more answers
Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?
mrs_skeptik [129]
8, 16, 32, 64,…
 ×2  ×2  ×2

a_{n} = a_{1} * r^{n - 1}
a_{n} = 8 * 2^{13 - 1}
a_{n} = 8 * 2^{12}
a_{n} = 8 * 4096
a_{n} = 32768

           First Term: 8
      Second Term: 16
          Third Term: 32
        Fourth Term: 64
           Fifth Term: 128
          Sixth Term: 256
     Seventh Term: 512
       Eighth Term: 1024
         Ninth Term: 2048
        Tenth Term: 4096
   Eleventh Term: 8192
     Twelfth Term: 16384
Thirteenth Term: 32768

The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.

5 0
4 years ago
Read 2 more answers
There are 115 flowers on 7 trees. What is the unit rate of the flowers per tree? How many flowers on 22 trees?
melamori03 [73]

Answer: 16 flowers per tree, 352 flowers on 22 trees.

Step-by-step explanation:

115 flowers/ 7 trees= 16.4 flowers per tree

Since you can't have partial flowers, round down to 16 flowers per tree.

16 flowers per tree * 22 trees=352 flowers

4 0
2 years ago
Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.
valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}

On the other hand, the distance form P to B is equal to d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}

Take the square in both sides of this equation to get

(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2

(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0

You can simplify using difference of squares and multiplying like this:

(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0

14x-10y-8z+36=0

which is the equation of a plane.

4 0
4 years ago
1. The value -2 is a lower bound for the zeros of the function shown below. f(x)=4x^3-12x^2-x+15
Alekssandra [29.7K]
First is false i believe
3 0
3 years ago
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