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kap26 [50]
3 years ago
9

Solve for x. Brainlest for anyone who helps!! thanks you

Mathematics
1 answer:
gavmur [86]3 years ago
6 0
<h3>Answer:  C) 0</h3>

================================================

Explanation:

If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.

(VS + UT)/2 = FE

(29 + x+17)/2 = 23 ... plug in given info; isolate x

(x+46)/2 = 23

x+46 = 23*2 ... multiply both sides by 2

x+46 = 46

x = 46-46 ... subtract 46 from both sides

<h3>x = 0</h3>
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A sector of a circle has a central angle of 100 degrees. If the area of the sector is 50pi, what is the radius of the circle
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The radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is <u>6√5 units</u>.

An area of a circle with two radii and an arc is referred to as a sector. The minor sector, which is the smaller section of the circle, and the major sector, which is the bigger component of the circle, are the two sectors that make up a circle.

Area of a Sector of a Circle = (θ/360°) πr², where r is the radius of the circle and θ is the sector angle, in degrees, that the arc at the center subtends.

In the question, we are asked to find the radius of the circle in which a sector has a central angle of 100° and the area of the sector is 50π.

From the given information, the area of the sector = 50π, the central angle, θ = 100°, and the radius r is unknown.

Substituting the known values in the formula Area of a Sector of a Circle = (θ/360°) πr², we get:

50π = (100°/360°) πr²,

or, r² = 50*360°/100° = 180,

or, r = √180 = 6√5.

Thus, the radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is <u>6√5 units</u>.

Learn more about the area of a sector at

brainly.com/question/22972014

#SPJ4

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