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2 years ago

What is this problem ?

Mathematics

1 answer:

Ede4ka [16]2 years ago

8 0

Answer:

=100000

Step-by-step explanation:

(10^2)(10^3)

=10^2*10^3

=(10*10)*(10*10*10)

=10*10*10*10*10

=105

=100000

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Equation 1<br> -3x -5 = 16<br> Equation 2<br> -4 (y - 2) = 12<br> What is the value of x and y

dangina [55]

Answer: Um, the value of x and y is x=–7, y=–1, I’m not sure my answer is going to be wrong or right, please tell me the correct answer.

Step-by-step explanation:

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2 years ago

Simplify 5 m - 13 M - n + 4 m

mel-nik [20]

Answer: -4m-n

Step-by-step explanation:

5m-13m-n+4m

5m-13m+4m-n

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7 0

3 years ago

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A^2 + b^2 + c^2 = 2(a − b − c) − 3. (1) Calculate the value of 2a − 3b + 4c.

Verdich [7]

Answer:

$2a - 3b + 4c = 1$

Step-by-step explanation:

Given

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Required

Determine $2a - 3b + 4c$

$a^2 + b^2 + c^2 = 2(a - b - c) - 3$

Open bracket

$a^2 + b^2 + c^2 = 2a - 2b - 2c - 3$

Equate the equation to 0

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 3 = 0$

Express 3 as 1 + 1 + 1

$a^2 + b^2 + c^2 - 2a + 2b + 2c + 1 + 1 + 1 = 0$

Collect like terms

$a^2 - 2a + 1 + b^2 + 2b + 1 + c^2 + 2c + 1 = 0$

Group each terms

$(a^2 - 2a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

Factorize (starting with the first bracket)

$(a^2 - a -a + 1) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$(a(a - 1) -1(a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1) (a - 1)) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + 2b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b^2 + b+b + 1) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + (b(b + 1)+1(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)(b + 1)) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + 2c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c^2 + c+c + 1) = 0$

$((a - 1)^2) + ((b + 1)^2) + (c(c + 1)+1(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)(c + 1)) = 0$

$((a - 1)^2) + ((b + 1)^2) + ((c + 1)^2) = 0$

Express 0 as 0 + 0 + 0

$(a - 1)^2 + (b + 1)^2 + (c + 1)^2 = 0 + 0+ 0$

By comparison

$(a - 1)^2 = 0$

$(b + 1)^2 = 0$

$(c + 1)^2 = 0$

Solving for $(a - 1)^2 = 0$

Take square root of both sides

$a - 1 = 0$

Add 1 to both sides

$a - 1 + 1 = 0 + 1$

$a = 1$

Solving for $(b + 1)^2 = 0$

Take square root of both sides

$b + 1 = 0$

Subtract 1 from both sides

$b + 1 - 1 = 0 - 1$

$b = -1$

Solving for $(c + 1)^2 = 0$

Take square root of both sides

$c + 1 = 0$

Subtract 1 from both sides

$c + 1 - 1 = 0 - 1$

$c = -1$

Substitute the values of a, b and c in $2a - 3b + 4c$

$2a - 3b + 4c = 2(1) - 3(-1) + 4(-1)$

$2a - 3b + 4c = 2 +3 -4$

$2a - 3b + 4c = 1$

7 0

3 years ago

So if a video that is 15:34 how long is it when 2 times speed

rusak2 [61]

Answer:

7:47

Step-by-step explanation:

Here are two ways of solving this:

The video will be half the time of 15:34, so you need to divide the time 15:34 by 2.

Method 1)

Use the tip. The video is 15 minutes and 34 seconds long.

Convert minutes to seconds: 15 * 60 = 900

Add 34 seconds to the 15 minutes: 900 seconds + 34 seconds = 934 seconds

The video is 934 seconds long.

Divide the total seconds by 2: 934/2 = 467

467 seconds = 420 seconds + 47 seconds = 7 minutes and 47 seconds

Answer: 7:47

Method 2)

Divide the minutes by 2 and divide the seconds by 2.

15 minutes and 34 seconds.

Divide minutes by 2: 15/2 = 7.5

Divide seconds by 2: 34/2 = 17

Now we need to add 7.5 minutes and 34 seconds.

0.5 minutes is half a minute, so it's 30 seconds.

7.5 minutes + 17 seconds =

= 7 minutes + 0.5 minute + 17 seconds

= 7 minutes + 30 seconds + 17 seconds

= 7 minutes + 47 seconds

= 7:47

Answer: 7:47

6 0

3 years ago

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Sedbober [7]

You did not put a question

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2 years ago

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