ALWAYS WEAR EYE PROTECTION.
Wear the RIGHT SAFETY EQUIPMENT for the job.
Use tools that are the RIGHT SIZE & RIGHT TYPE for your job.
Follow the correct procedure for using EVERY tool.
Keep your cutting tools SHARP and in good condition.
DON'T work with OILY or GREASY hands.
Answer:
She lost $754.05.
Explanation:
Giving the following information:
Liz Mulig earns 52,000 per year as a philosophy professor. She receives a raise of 2.5% in a year in which CPI increases by 3.8%.
<u>The rise in her salary allows her to increase her purchasing power. On the contrary, inflation decreases purchasing power. We need to calculate the differences between both effects and determine whether she can buy more or less.</u>
<u></u>
Increase in salary= 52,000*1.025= $53,300
Inflation effect= 52,000/(1-0.038)= $54,054.05
To maintain her purchasing power, now, she needs to earn $54,054.05.
She lost $754.05.
Question Completion with options:
Select one:
a. Include the $5,000 in total income on Form 1040
b. Include the $5,000 as a capital gain on Schedule D
c. Include the $5,000 as self-employment income on Schedule C
d. Include the $5,000 as interest income on Form 1040
Answer:
Loc Nguyen should:
b. Include the $5,000 as a capital gain on Schedule D.
Explanation:
Both long-term and short-term capital gains and deductible capital losses are reported on Schedule D of Form 1040. If the gain from the sale of the boat is a long-term capital gain, it will be subject to the lower capital gain tax rate of up to 20%, unlike the short-term capital gain that attracts a rate of up to 37%.
Answer:
Option (d) , Bank 4 offers the highest amount after a year
Explanation:
The total amount from each of the interest rates can be expressed as;
A=P(1+r/n)^nt
where;
A=Future value of investment
P=Initial value of investment
r=Annual interest rate
n=Number of times the interest is compounded annually
t=number of years of the investment
a). Bank 1
P=x
r=6.1%=6.1/100=0.061
n=1
t=assume number of years=1
replacing;
A=x(1+0.061/1)^(1×1)
A=x(1.061)
A=1.061 x
b). Bank 2
P=x
r=6%=6/100=0.06
n=12
t=1
Replacing;
A=x(1+0.06/12)^(12×1)
A=x(1.005)^12
A=1.0617 x
c). Bank 3
P=x
r=6%=6/100=0.06
n=1
t=1
Replacing;
A=x(1+0.06/1)^(1)
A=1.0600 x
d). Bank 4
P=x
r=6%=6/100=0.06
n=4
t=1
A=x(1+0.06/4)^(4×1)
A=x(1+0.015)^4
A=x(1.061)
A=1.0614 x
e). Bank 5
P=x
r=6%=6/100=0.06
n=365
t=1
A=x(1+0.06/365)^(365×1)
A=1.0618
Option (d) , Bank 4 offers the highest amount after a year
