by pythagorean formula, the last side is √(61)
by cos rule
cos A
![= \frac{ {6}^{2} + 61 - {5}^{2} }{2 \times 6 \times \sqrt{61} } \\ = \frac{72}{12 \sqrt{61} } \\ = \frac{6}{ \sqrt{61} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%7B6%7D%5E%7B2%7D%20%20%2B%2061%20-%20%20%7B5%7D%5E%7B2%7D%20%7D%7B2%20%5Ctimes%206%20%5Ctimes%20%20%5Csqrt%7B61%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B72%7D%7B12%20%5Csqrt%7B61%7D%20%7D%20%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B6%7D%7B%20%5Csqrt%7B61%7D%20%7D%20)
A = 39.81
A toy cost 0.85p in January.
Step-by-step explanation:
Given,
Mark down in January = 15%
Let,
Price in December = p
Mark down in January = 15% of price in December
Mark down in January = ![\frac{15}{100}*p](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B100%7D%2Ap)
Mark down in January = 0.15p
Price of toy in January = Price in December - Mark down
Price of toy in January = p - 0.15p = 0.85p
A toy cost 0.85p in January.
Keywords: mark down, subtraction
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An = a1 * r^(n-1)
n = term to find = 18
a1 = first term = 3
r = common ratio = 4/3
now we sub
a18 = 3 * 4/3^(18 - 1)
a18 = 3 * 4/3^17
a18 = 3 * 133
a18 = 399
Answer:
It is a GP.
Step-by-step explanation:
a = 3
r = 2
a(n) term = ar^n
As it increases as multiples, it is a geometric progression or a GP.
Answer:
A) x=6
Step-by-step explanation:
6.5^2-2.5^2=x^2
42.25-6.25=x^2=36
x=6