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3 years ago

6

Joe's employer will reimburse him $0.07 per mile driven. If Joe drives 179.53 miles on a business trip, what is his mileage reim

bursement? Round your answer to the nearest cent.

1 answer:

Reika [66]3 years ago

3 0

Answer:

$12.27

Step-by-step explanation:

.07 times 179.53 is 12.5671 so rounded to 12.27

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a chord is drawn 3 cm away from the centre of a circle of radius 5 cm. calculate the length of the chord

lara [203]

Answer:

8 cm

Step-by-step explanation:

the 3 cm line from the chord to the center of a circle is a leg of a right triangle which perpendicularly bisects the chord into two equal halves

draw the hypotenuse of the right triangle from the center of the circle to the endpoint of the chord. This is a radius measuring 5 cm.

find the missing leg of the right triangle

a^2= c^2- b^2

a^2= 25-9

a^2=16

a=4

this is only the measurement of half the chord. To find the full length of the chord multiply by two

4*2=8 cm

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3 years ago

Which rate is faster:a bird traveling at a constant rate of 2 kilometer per hour or an insect travelinf at a constant rate of 1,

Alla [95]

The bird since 1 kilometer is 1000 meters

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3 years ago

"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e

Art [367]

Answer:

a. v(t)= -6.78 $e^{-16.33t}$ + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)= $e^{\int\limits^ {}k \, dt }$ = $e^{kt}$ . We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ $e^{kt}$ v' + k $e^{kt}$ v = g $e^{kt}$ ⇒ [v $e^{kt}$ ]' = g $e^{kt}$ . Integrating, we have

∫ [v $e^{kt}$ ]' = ∫g $e^{kt}$

v $e^{kt}$ = $\frac{g}{k}$ $e^{kt}$ + c

v(t)= $\frac{g}{k}$ + c $e^{-kt}$ .

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + c $e^{-16.33 * 0}$ = 16.33 + c

c = 9.55 -16.33 = -6.78.

So, v(t)= 16.33 - 6.78 $e^{-16.33t}$ . m/s = - 6.78 $e^{-16.33t}$ + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78 $e^{-16.33 x 0.5}$ + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

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3 years ago

Given that 3+√5/4−√5 = a + b√5, find the values of “a” and “b”<br>URGENT PLZ ANSWER!

Vikki [24]

Answer:

Step-by-step explanation:

hello :

√(5/4)= √5/ √4 =√5/2 = (1/2)√5

3+√5/4−√5 = 3+(1/2)√5 so : a=3 and b= 1/2

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4 years ago

You set up monthly recurring payments of $110.03, $45.66, and $22.87. How much will your recurring payments total over one year?

AlladinOne [14]

The answer is B 2,142.72 because when you add it all up then multiply by 12 it will equal that.

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3 years ago

Read 2 more answers