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Fynjy0 [20]
4 years ago
14

What is the average rate of change over the interval [-2,0] for the graph?​

Mathematics
1 answer:
Kisachek [45]4 years ago
3 0

A_r = \frac{\triangle y }{\triangle x} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - (-3)}{4 -(-3)} = \frac{1}{7}

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The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

So

Z = \frac{X - \mu}{\sigma}

1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

7 0
3 years ago
3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

x=\frac{y}{2}

\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

R_{o} = x = \frac{y}{2}

R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0
2 years ago
A giraffe can run 40 meters per second what is its speed in miles per hour
lora16 [44]
Bearing in mind that, there are

60 seconds in 1 minute,
60 minutes in 1 hr,
1000 meters in 1 km,
and 1.609 km in 1 mile

\bf \cfrac{40\underline{m}}{\underline{s}}\cdot \cfrac{60\underline{s}}{\underline{min}}\cdot \cfrac{60\underline{min}}{hr}\cdot \cfrac{\underline{km}}{1000\underline{m}}\cdot \cfrac{mi}{1.609\underline{km}}\implies \cfrac{40\cdot 60\cdot 60\cdot  mi}{hr\cdot 1000\cdot 1.609}&#10;\\\\\\&#10;\cfrac{144000mi}{1609hr}\approx 89.496581\frac{mi}{hr}
6 0
3 years ago
Is the association between x and y positive or negative?<br> A. none B.positive C, negative
Vinvika [58]

Answer:

A.non at all so, please choose the right answer

8 0
3 years ago
Read 2 more answers
How long will it take a seal swimming at a speed of 8 miles per hour to travel 52 miles
Olin [163]
8\ miles\ per\ 1\ hour\\&#10;52\ miles\ per\ x\ hour\\\\&#10;proportion:\\&#10;8-1\\52-x\\\\cross\ multiplication\\\\&#10;8x=52\ \ \ | divide\ by\ 8\\\\&#10;x=6.5\\\\&#10;It\ will\ take\ 6.5\ hours.
7 0
3 years ago
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