Answer:
What is the first part of the question? Can you put it in the comments?
Step-by-step explanation:
This is a great question!
To determine the probability with which two sweets are not the same, you would have to subtract the probability with which two sweets are the same from 1. That would only be possible if she chose 2 liquorice sweets, 5 mint sweets and 3 humburgs -

As you can see, the first time you were to choose a Liquorice, there would be 12 out of the 20 sweets present. After taking that out however, there would be respectively 11 Liquorice out of 19 remaining. Apply the same concept to each of the other sweets -

____
Calculate the probability of drawing 2 of each, add them together and subtract from one to determine the probability that two sweets will not be the same type of sweet!

<u><em>Thus, the probability should be 111 / 190</em></u>
Answer:
4ab
Step-by-step explanation:
(a+b)^2-(a-b)^2
=a^2 + 2ab + b^2 -(a^2 - 2ab +b^2)
=a^2 + 2ab + b^2 - a^2 + 2ab - b^2
=2ab + 2ab
=4ab
It's not specific enough to solve...so far it would only be f(3)
Answer:
i cant show you how to but use desmos graphing calculator, copy and paste that equation and it will do it for you
Step-by-step explanation: