I assume you are trying to solve for each variable. if thats the case you want to use one equation to solve for y and then plug the y value into the next variable
Problem: y =-3x=4 so -3x+4=3x-2
x=1
plug x value into one of the equations
y=3(1)-2
y=1
1/4 x 16
= 16 ÷ 4
= 4
1/3 x 24
= 24 ÷ 3
= 8
8 is greater than 4, so one third of 24 is bigger than one fourth of 16
feel free to ask questions if you are still confused!
5x+6=2x+15
-2x -2x
3x+6=15
-6 -6
3x=9
/3 /3
x=3
The number of $0.50 increases to maximize the profit is X = 1.
First of all, we need to write the linear function which represents the price of the ticket for each increase of $0.50:
P - Price of each ticket.
x - number of increases.
We know that the current price is $5.00, so:

After that, let's build a linear function which shows the number of tickets sold <u>for each</u> price increase:
T - number of tickets.
x - number of increases.

With all this done, we can finally build the quadratic function which represents the money earned:
M - money earned

Now, to finish, we only have to <u>calculate the value of X</u>(number of increases) which can give us the maximum value of this function:
the X coordinate for the maximum value of a quadratic is expressed by:

In our equation, b = 100 and a = - 50 :

Thus, the number of increases which <u>maximizes</u> the profit is 1.
Learn more about linear and quadratic functions in: brainly.com/question/4119784