Answer:
The coordinates of the point S = (12, -22)
Step-by-step explanation:
The coordinate points of T = (0,6)
Mid point of ST = (6,-8)
Let the coordinates of S = (a,b)
Now, BY MID POINT FORMULA:
If (x, y) and (z, w) are the line point joining line segment and (p,q) is the coordinate of mid point. Then
So, here similarly,
⇒
⇒ a =2 x 6 = 12, b = 2 (-8) -6 = -22
⇒(a,b) = (12, -22)
Hence, the coordinates of the point S = (12, -22)
Answer: B. (x - 1) (x - 4)
Concept:
Here, we need to know the idea of zeros.
The zeros of a quadratic equation are the points where the graph of the quadratic equation crosses the x-axis.
If you are still confused, please refer to the attachment below for a graphical explanation.
Solve:
By definition, the factored form of quadratic equations is basically their zeros.
<u>STEP ONE: Find the zeros / x-intercept of the graph</u>
The grid number is 2 per grid as 5 grids are 10 units.
The first intercept is between the y-axis and the first grid.
The second intercept is on the second grid.
<u>STEP TWO: Plug the zeros into factorization form</u>
Factor form = (x - x₁) (x - x₂)
x₁ = (1, 0)
x₂ = (4, 0)
Factorization of x² - 5x + 4 = (x - 1) (x - 4)
Hope this helps!! :)
Please let me know if you have any questions
