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3 years ago

Which point is one the graph of f(x) = 2 * 5^x?

Mathematics

1 answer:

marusya05 [52]3 years ago

7 0

Answer:

(0,2)

Step-by-step explanation:

I'm going to assume you meant Which point is ON the graph of f(x) = 2 * 5^x?

In order to do this question, all you need to do is pick any number as x. Lets pick 0 in this case.

f(x) = 2 * 5^x

f(0) = 2*5^0

= 2*1

= 2

So one point on the graph would be (0,2)

Why?

Because remember with functions, the f(x) can be swapped out with y, so when x = 0, y = 2.

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Help me please!!! I give more points and brainliast please help me!

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Hey there!!

Fill in the blanks :-

⇒ First graph the line. Locate the value of x on the x-axis. Draw a vertical line from point plotted on the x-axis to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.

Find the value of f(x) when x is -2.

$f(x) = \frac{3}{2}x-4$

Remember :- f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x.

Given : x = - 2

Plugging in the values :

... $f(-2) = \frac{3*(-2)}{2}-4$

... $f(-2) = \frac{-3}{1} - 4$

... $f(-2) = -7$

The last fill in the blank :

The value of y on the y-axis is the value of the function. Therefore, the value of f(x) is -7 when x is -2.

Hope it helps!!

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3 years ago

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guajiro [1.7K]

Answer:

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Step-by-step explanation:

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3 years ago

System: -5x + 3y = 6 Y=7x - 14 (Solve with substitution) Find the x,y

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Answer:

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Step-by-step explanation:

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3 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0

3 years ago