Standard formula for arithmetic sequence:
an = a0 + d(n-1)
if we use the two terms given, setting a12 as starting term and a45 as the end term an.
170 = 38 + 33d
170 - 38 = 33d
132 = 33d
132/33 = d
This is the common difference, use it to find the first term.
38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0
The starting term is -6
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Answer:
B. -13
Step-by-step explanation:
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Solving this inequality:
-6>t-(-13)
solve as an equation;
6>t+13
6-13>t
-7>t
-7 is greater than t, which means that can be any number smaller that t, fir instance -8, -22 etc.
<span>The answer is (change of amount) / (change of time). For the change of amount, the numerator is 40 seagulls - 16 seagulls, leaving a total of 24 seagulls. For the change of time, the denominator is 3 pm - 1 pm, leaving a total of a 2 hour difference. The answer becomes 24 seagulls / 2 hours, or 12 seagulls per hour when simplified.</span>
