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Tresset [83]
3 years ago
9

Claire is 2 year younger than her sister. The

Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Given:

Claire is 2 year younger than her sister.

The  sum of ages is no less than 44 years.

To find:

Inequality and find the youngest age Claire can  be.

Solution:

Let the age of Claire be x.

Her sister's age = x+2

Sum of their ages is no less than 44 years. It means the sum ages is greater than or equal to 44.

x+(x+2)\geq 44

2x+2\geq 44

2x\geq 44-2

2x\geq 42

Divide both sides by 2.

x\geq 21

It means, Claire age can be greater than or equal to 21. So, the youngest age Claire can  be 21 years old.

Therefore, the required inequality is  2x+2\geq 44 and the correct option is B.

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B400%20%5Ctimes%20400%20-%2024%20%5Ctimes%20400%20-%20360%20%5Ctimes%20400%20-%202
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\sqrt{400 \times 400 - 24 \times 400 - 360 \times 400 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\ = \sqrt{160000 - 153,800} \\  \\  = \sqrt{6200} \\  \\  = 78.74 \\  \\

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Jed Sites
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Option B: 3x + 3y - 3

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In an isosceles triangle, the two congruent sides are equal.

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