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Natalka [10]
3 years ago
11

In multiple regression analysis, residuals (Y - Ŷ) should be ____________. Qualitative variables Normally distributed with a mea

n of zero Significantly different from zero Correlated
Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

Normally distributed with a mean zero.

Step-by-step explanation:

In multiple regression analysis, residuals \left ( Y-\hat{Y} \right ) should be Normally distributed with a mean zero.

               In general, multiple regression is a technique to find more about the connection between many independent variables and dependent variables. It is simple a modern approach of a simple linear regression.

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Sherman has 3 cats and 2 dogs. He wants to buy a toy for each of his pets. Sherman has $22 to spend on pet toys. How much can he
umka2103 [35]

Sherman can spend $4.40 om all five of his pets

3 0
4 years ago
Read 2 more answers
I need help with this problem, the link is below!
lilavasa [31]
<h3>Answer:</h3>

m∠QSW < m∠WQS

<h3>Explanation:</h3>

The question is asking which angle is larger, the one at vertex S or the one at vertex Q? You are expected to understand how angles are named and how angle measure works.

Angles are named by listing points on the rays that make them up, with the vertex point in the middle of the list. ∠QSW is the angle whose vertex is at S. (Since there is only one angle with its vertex at S, it could also be called ∠S.) The letters Q and W help you identify that rays SQ and SW form the sides of the angle.

Likewise, ∠WQS is the angle whose vertex is at Q. It could also be called ∠Q without any confusion. The other letters in the name tell you that rays QW and QS are the sides of the angle.

When the rays that make the sides of an angle are closer together, the angle has a smaller measure.

In a triangle, there are a several different ways to determine which of the angles is larger.

  • the larger angle will be opposite the longer side
  • the base point of an altitude line will be closer to the larger (acute) angle
  • the rays that make up the larger angle will be farther apart (at some given radius from the vertex)
  • relative to a perpendicular bisector between the vertices, the vertex of the third angle will be on the side closer to the larger angle (another way to say the relationship of the second point above)

_____

<em>Your triangle</em>

Line segment QW (opposite ∠S) is shorter than line segment SW (opposite ∠Q) so m∠S < m∠Q.

A line segment drawn from W perpendicular to QS is closer to Q, so ∠Q is the larger angle.

Thus we must conclude the measure of ∠QSW is less than the measure of ∠WQS:

... m∠QSW < m∠WQS

_____

<em>Comment on appearances</em>

Here, you're specifically told to go by the appearance of the angles. In most cases, you cannot, as the figures are rarely drawn to scale, and are often drawn to be intentionally misleading.

7 0
3 years ago
1. What is the Potential Energy of a 6 kg object that is 10 m above the<br> ground?
andriy [413]
PE = mgh
m = 6 kg, g = 9.8 m/s^2, h = 10m
6 * 9.8 * 10 = 588 J
5 0
3 years ago
Which ordered pair is not a solution of f(x) = 2x + 9? A. (0,9) B. (7, 23) C.(3, 14) D.(2, 13)​
Paladinen [302]

Answer:

The answer is C (3, 14)

6 0
4 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
xxTIMURxx [149]

Step-by-step explanation:

Let the initial population of a community be P0 and the population after time t is P(t).

If the population of a community is known to increase at a rate proportional to the number of people present at time t, this is expressed as:

P(t) = P_0e^{kt}

at t = 5 years, P(t) = 2P0

substitute:

2P_0 = P_0e^{5k}\\2 = e^{5k}\\ln2 = lne^{5k}\\ln2 = 5k\\k = \frac{ln2}{5}\\k = 0.1386

If the population is 9,000 after 3 years

at t = 3, P(t) = 9000

a) Substitute into the formula to get P0

9000 = P_0e^{0.1386\times 3}\\9000 = P_0e^{0.4158}\\9000 = 1.5156P_0\\P_0 = \frac{9000}{1.5156}\\ P_0 = 5938.24

Hence the initial population is approximately 5938.

b) In order to know how fast the population growing at t = 10, we will substitute t = 10 into the formula as shown:

P(10) = 5938.24e^{0.1386(10)}\\P(10) = 5938.24e^{1.386}\\P(10) = 5938.24(3.9988)\\P(10) = 23,745.97

Hence the population of the community after 10 years is approximately 23,746

4 0
4 years ago
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