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Dafna11 [192]
3 years ago
13

What % is 17 of 25 ?

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
17/25 would equal to 68%
lapo4ka [179]3 years ago
7 0
68% is the answer ....
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Kim read 4/5 of her book and Grace read 6/10 of her book. who read more of her book, kim or Grace?
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Kim did. Make the fractions into decimals(4 divided by 5, 6 divided by 10) Kim got 0.8, while Grace got 0.6.
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3 years ago
What is the answer to 1.3 (6.3r - 4.2) = 66.9
liubo4ka [24]
R = 804/91


8.835

this is ur answer i how i helped
5 0
3 years ago
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Lcm of 2²×3×5²and2²×3²×5​
Bingel [31]

Answer:

580

Step-by-step explanation:

because you square the area and identify

4 0
3 years ago
find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis
antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0

Which means that the roots are

x=0\ \lor\ x=1\ \lor\ x=-2

Next, we can expand the function definition:

y = x(x-1)(x+2) = x^3 + x^2 - 2x

In this form, it is much easier to compute the derivative:

y' = 3x^2+2x-2

If we evaluate the derivative in the points of interest, we have

y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

y-y_0=m(x-x_0)

is what we need. The three lines are:

y-0=6(x+2) \iff y = 6x+12  This is the tangent at x = -2

y-0=-2(x-0) \iff y = -2x  This is the tangent at x = 0

y-0=3(x-1) \iff y = 3x-3  This is the tangent at x = 1

7 0
2 years ago
Triangles E F G and K L M are shown. Angles E F G and K L M are congruent. The length of side K L is 6, the length of side M L i
Masteriza [31]

Answer:

The Answer is C: Yes, △EFG~ △KLM by SSS or SAS

Step-by-step explanation:

SSS is for side-side-side

Both triangles have all three sides given, so the SSS similarity theorem is one way to prove these triangles are similar.

SAS is for side-angle-side

Both triangles have one angle measurement given, and two side lengths given, therefore we can also use the SAS similarity theorem to prove the two triangles are similar.  

Since both SSS and SAS work to prove the triangles are similar, the correct answer is C: Yes, △EFG~ △KLM by SSS or SAS

(I also just answered this question on the assignment and got it correct)

3 0
2 years ago
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