Answer:
170 that is the answer hope it's right
Answer:
what is the problem
Step-by-step explanation:
5(2)>3(1)+4
10 > 7. Is True because 10 is greather than 7. All needed to do is evaluate the x and y variables for each possibility. A, B, C D. And see if is a logical answer.
Any other combination gives you a false statement.
<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
Q1
r = (2A/θ)^.5 = ((14/(1/8))^.5 = 10.583 ft <--------
q2
θ = 2A/r^2 = 2*3/7^2 = .122 rad <--------
