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3 years ago

Isabella uses the equation to find the volume of the cone below.

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

The correct answer option is: Isabella should have divided the product of $12\pi$ and 9 by 3 to get $V=\frac{12\pi (9)}{3}$

Step-by-step explanation:

We are given a diagram of a cone with height $9 cm$ and area of the base (circle) $12 \pi cm^ 2$ .

Isabella uses the equation $V = \frac { 1 } { 3 } ( 12 ) ^ 2 ( 9 ) \pi$ and we are to find the error that she is making in finding the volume of this cone.

The volume of a cone is given by: $\pi r^2\frac{h}{3}$ out of which $\pi r^2$ represents the area of the base (circle).

Therefore, Isabella should have divided the product of $12\pi$ and 9 by 3 to get $V=\frac{12\pi (9)}{3}$ .

sergey [27]3 years ago

8 0

The answer is in fact D or Isabella should have divided the product of 12 Pie and 9 by 3 to get V= 12 Pie (9)/3

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Please help me solve this and please also show work so I can understand it BETTER PLEASEEE ITS DUE

ratelena [41]

Answer:

6. 8b²-5b-4

7. -3x²+9x-4

8. 3

9. 6a+15

Step-by-step explanation:

you will subtract/add the numbers with the same variables and exponent.

ex. (number 6) 7b²+ b²= 8b²

5b= 5b 8b²+5b-4

1-5= -4

(plus 5b because it didnt come out to a negative) if you have any questions, say in the comments and ill try my best to help

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3 years ago

Please help me understand how to solve equations like these, I don’t understand them:

algol [13]

Answer:

subtract the unwanted b term
divide by the coefficient of b
b = 60

Step-by-step explanation:

The numbers 4/5 and 9/10 are fractions. They multiply the variable 'b' in each case.

How to solve an equation like this

An example of an equation like this without fractions is ...

6 + 3b = 8b

You solve this sort of equation by rearranging the equation so the terms having 'b' in them are all on one side of the equal sign. You want all of the terms not containing 'b' to be on the other side of the equal sign.

Here, the terms are mixed on the left, but the right has only a 'b' term. So, if we can remove the 'b' term from the left side, we will have reached the goal

In the example equation, we do that by adding -3b to both sides of the equation.

6 +3b -3b = 8b -3b

Simplifying, we have ...

6 = 5b

Now, we divide by the coefficient of 'b', which is 5. We divide both sides of the equation by that:

6/5 = (5b)/5

6/5 = b . . . . after simplifying

_____

How to solve this equation

The given equation is solved exactly the same way. We add the opposite of the 'b' term that we don't want (which is 4/5b):

6 + 4/5b -4/5b = 9/10b -4/5b

Simplifying, this is ...

6 = (9/10 -4/5)b = (9/10 -8/10)b

6 = 1/10b

We can make the coefficient of 'b' be 1 by multiplying it by 10. We have to do that to both sides of the equation:

(10)(6) = (10)(1/10)b

60 = b . . . . . the solution

_____

Comment on equations in general

The one absolute rule in Algebra is that the equal sign must remain valid. You keep that commandment by observing the properties of equality. Essentially, you can do anything you like to one side of an equation, as long as you do exactly the same thing to the other side.

Here, when we say "subtract 4/5b", the way we keep this commandment is that we do it to both sides of the equation. The same is true for "multiply by 10". This is emphasized by the bold highlighting in the solution shown above.

Comment on arithmetic

In solving this equation, we did the arithmetic using the given fractions. Often, for an equation like this, you will be told the first step is to "eliminate fractions". You can do that here by multiplying the equation by 10:

10(6 +4/5b) = 10(9/10b)

60 +8b = 9b

Now, the unwanted term is 8b, so subtracting that (from both sides) gives ...

60 = b

This is essentially a "2-step" equation, either way you do it.

It is helpful if you are comfortable doing arithmetic with fractions, mixed numbers, decimals, percentages, and numbers in scientific notation, as well as integers.

4 0

3 years ago

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.75241,0.06281)$