Isabella uses the equation to find the volume of the cone below.

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Answer:

The correct answer option is: Isabella should have divided the product of $12\pi$ and 9 by 3 to get $V=\frac{12\pi (9)}{3}$

Step-by-step explanation:

We are given a diagram of a cone with height $9 cm$ and area of the base (circle) $12 \pi cm^ 2$ .

Isabella uses the equation $V = \frac { 1 } { 3 } ( 12 ) ^ 2 ( 9 ) \pi$ and we are to find the error that she is making in finding the volume of this cone.

The volume of a cone is given by: $\pi r^2\frac{h}{3}$ out of which $\pi r^2$ represents the area of the base (circle).

Therefore, Isabella should have divided the product of $12\pi$ and 9 by 3 to get $V=\frac{12\pi (9)}{3}$ .

sergey [27]3 years ago

8 0

The answer is in fact D or Isabella should have divided the product of 12 Pie and 9 by 3 to get V= 12 Pie (9)/3

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Leno4ka [110]

Answer:

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hope this helps

Step-by-step explanation:

4 0

3 years ago

Please help, The wording is throwing me off so badly.

sweet [91]

first off, let's recall that a cube is just 6 squares stacked up to each other, like in the picture below. Since we know its volume, we can find how long each side is.

part A)

$\bf \textit{volume of a cube}\\\\V=x^3~~\begin{cases}x=side\\[-0.5em]\hrulefill\\V=64\end{cases}\implies 64=x^3\implies \sqrt[3]{64}=x\implies 4=x$

part B)

they have a painting with an area of 12 ft², will the painting fit flat against a side? Well, it can only fit flat if the sides of the painting are the same length or smaller than the sides of the crate, we know the crate is a 4x4x4, so are the painting's sides 4 or less?

$\bf \textit{area of a square}\\\\A=s^2~~\begin{cases}s=side\\[-0.5em]\hrulefill\\A=12\end{cases}\implies 12=s^2\implies \sqrt{12}=s\implies \stackrel{yes}{3.464\approx s}$