Answer:
This is a geometric progresion that begins with 1 and each term is 1/3 the preceeding term
Let Pn represent the nth term in the sequence
Then Pn = (1/3)^n-1
From this P14 = (1/3)^13 = 1/1594323
5. The sum of the first n terms of a GP beginning a with ratio r is given by
Sn = a* (r^n+1 - 1)/(r - 1)
With n = 10, a = 1 and r = 1/3, S10 = ((1/3)^11 - 1)/(1/3 - 1) = 1.500
318-47= 271 There are 271 non-fiction books in the library. just subtract 47 from 318 to get the answer.
Answer:
31
Step-by-step explanation:
i have no idea if that is right
I think the question is supposed to be 45/3 which will give 15.The prime factorization of 15 is simply splitting 15 into product of prime factors, which is 3*5.
Please mark me as brainliest.
