<h3>
Answer:</h3>
<u>Perimeter of rectangular garden = 2(l + b)</u>
- 2(y + 2 + 4y - 1)
- 2y + 4 + 8y - 2
- 10y + 2.
<u>Hence, perimeter of given garden is 10y + 2</u>.
Step-by-step explanation:
12,0,-12
![a1 = 12 \\ a2 = 0 \\ d = a2 - a1 \\ d = 0 - 12 = - 12 \\ an = a1 + (n - 1) \times d \\ \\ a87 = 12 + (87 - 1) \times ( - 12) \\ a87 = 12 - 1032](https://tex.z-dn.net/?f=a1%20%3D%2012%20%5C%5C%20a2%20%3D%200%20%5C%5C%20d%20%3D%20a2%20-%20a1%20%5C%5C%20d%20%3D%200%20-%2012%20%3D%20%20-%2012%20%5C%5C%20an%20%3D%20a1%20%2B%20%28n%20-%201%29%20%5Ctimes%20d%20%5C%5C%20%20%5C%5C%20a87%20%3D%2012%20%2B%20%2887%20-%201%29%20%5Ctimes%20%28%20-%2012%29%20%20%5C%5C%20a87%20%3D%2012%20%20-%201032)
He will use 80% of the stock compared to the original recipe.
The total Surface Area of a right Cone is the sum of the area of its base and the lateral (side) surface.
The formula for the total surface area of a right cone is ![T.S.A=\pi rl+\pi r^2](https://tex.z-dn.net/?f=%20T.S.A%3D%5Cpi%20rl%2B%5Cpi%20r%5E2%20)
Where r is the radius, and l is the slant height
well, to get the slope of any line, we only need two points, hmmm let's see, from the points there, we can use say, (-4, 5) and (0, 6).
![\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{5})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{6})\\\\\\slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-5}{0-(-4)}\implies \cfrac{6-5}{0+4}\implies \cfrac{1}{4}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-4%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%28%5Cstackrel%7Bx_2%7D%7B0%7D~%2C~%5Cstackrel%7By_2%7D%7B6%7D%29%5C%5C%5C%5C%5C%5Cslope%20%3D%20m%5Cimplies%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B6-5%7D%7B0-%28-4%29%7D%5Cimplies%20%5Ccfrac%7B6-5%7D%7B0%2B4%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B4%7D)