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kogti [31]
3 years ago
10

Corresponding solution for 6=1/3x+5

Mathematics
2 answers:
Westkost [7]3 years ago
4 0

Let's solve your equation step-by-step.

6=

1

3x

+5

Multiply all terms by x and cancel:

6x=

1

3

+5x

6x=5x+

1

3

(Simplify both sides of the equation)

6x−5x=5x+

1

3

−5x(Subtract 5x from both sides)

x=

1

3

Check answers. (Plug them in to make sure they work.)

x=

1

3

(Works in original equation)

Answer:

x=

1

3


zaharov [31]3 years ago
4 0

6 -5 = 1/3x

1 =1/3x   # divided both side by 3/1 to isolate x by itself

then you get x = 3


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The axis of symmetry for the function f(x) = –2x2 + 4x + 1 is the line x = 1. Where is the vertex of the function located?
egoroff_w [7]

Answer:

(1, 3)

Step-by-step explanation:

You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola.  The first few steps are as follows.  Set the parabola equal to 0 so you can solve for the vertex.  Separate the x terms from the constant by moving the constant to the other side of the equals sign.  The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out).  Let's start there.  The first 2 steps result in this polynomial:

-2x^2+4x=-1.  Now we factor out the -2:

-2(x^2-2x)=-1.  Now we complete the square.  This process is to take half the linear term, square it, and add it to both sides.  Our linear term is 2x.  Half of 2 is 1, and 1 squared is 1.  We add 1 into the set of parenthesis.  But we actually added into the parenthesis is +1(-2).  The -2 out front is a multiplier and we cannot ignore it.  Adding in to both sides looks like this:

-2(x^2-2x+1)=-1-2.  Simplifying gives us this:

-2(x^2-2x+1)=-3

On the left we have created a perfect square binomial which reflects the h coordinate of the vertex.  Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:

-2(x-1)^2+3=y

From this form,

y=-a(x-h)^2+k

you can determine the coordinates of the vertex to be (1, 3)

5 0
3 years ago
Read 2 more answers
How did you get that ? 709 × 68= 48212?
algol13
You can get the answer by doing proper multiplication. In another words, it mean like this:
709
× 68
-----------
5672
+
4254
-----------
48212. To do this right, you need to rearrange this into the right position to get the correct answer. Also, you can use calculator to find the answer more quicker. Hope it help!
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3 years ago
The sector of a circle has an area of 104pi/9 square inches and a central angle with measure 65 degrees. What is the radious of
kompoz [17]

Answer: b. 8

Step-by-step explanation: I don’t have work

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3 years ago
Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim
tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{10959}{25} =438.36

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S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49

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Sample mean, \bar{x} = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813

Now, t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108

Since,                        

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

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Answer:

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Step-by-step explanation:

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