Answer:
0.7486 = 74.86% observations would be less than 5.79
Step-by-step explanation:
I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The general format of the normal distribution is:
N(mean, standard deviation)
Which means that:

What proportion of observations would be less than 5.79?
This is the pvalue of Z when X = 5.79. So



has a pvalue of 0.7486
0.7486 = 74.86% observations would be less than 5.79
Answer:
The average number of visitors per day is 272.
Step-by-step explanation:
Total number of visitors in the zoo in a year = 98,464
Now,we know that 1 YEAR = 365 DAYS
Also, the zoo was closed on thanksgiving, Christmas, and New Year's Eve
So, the Number of days zoo was open = Total Days in year - 3 days
= 365 - 3 = 362 days
⇒Number of visitors in 362 days = 98,464
So, 

or, the number of people visiting per day is 272.
Hence, the average number of visitors per day is 272.
The answer would be 17n+6.