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2 years ago

Simplify using the vertical method. (2k+3)(2k^2-4k-3)

1 answer:

4 0

4k^3 - 8k^2 + 6k^2 - 12k - 6k - 9
Combine like terms... -8k^2+6k^2= -4k^2
-12k+6k=-6k
and leave 4k^3 and -9 alone because you don't have anything to combine it with so the equation is 4k^3 -4k^2 -6k -9

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2. What property is shown with this

Verizon [17]

Answer:

Associative Property

Step-by-step explanation:Because it includes grouping of three numbers and the parentheses group around two different numbers

8 0

2 years ago

What is y=-4/3x +6. y=2

Mekhanik [1.2K]

The given equation is:
[/tex]y=-\frac{4}{3}x+6 [/tex] and we need to evaluate this for y=2.
So, first step is to plug in 2 for y in the above equation. Therefore,

$2=-\frac{4}{3} x+6$
$2*3=-\frac{4}{3} x*3+6*3$ Multiply each sides by common denominator 3
$6=-4x+18$
6-18= -4x Subtract 18 from each sides.
-12=-4x
$-\frac{12}{-4} =-\frac{4x}{-4}$
So, x=3

5 0

2 years ago

What's the answer for this?

salantis [7]

Here's a tip Subtracting a fraction is the same as multiplying it's reciprocal so for 3/4 - 3/8 you can do 3/4 x 8/3. Multiplying its reciprocal mean turn the 2nd fraction around

6 0

3 years ago

Read 2 more answers

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

2 years ago

Read 2 more answers

The admission fee at an amusement park is $2.00 for children and $6.80 for adults. On a certain day, 388 people entered the park

san4es73 [151]

Answer: 188 children and 200 adults were admitted

Step-by-step explanation:

Let x represent the number of children that were admitted.

Let y represent the number of adults that were admitted.

On a certain day, 388 people entered the park. It means that

x + y = 388

The admission fee at the amusement park is $2.00 for children and $6.80 for adults. The admission fees collected on that day totaled $1736. It means that

2x + 6.8y = 1736- - - - - - - - - - 1

Substituting x = 388 - y into equation 1, it becomes

2x + 6.8y = 1736

2(388 - y) + 6.8y = 1736

776 - 2y + 6.8y = 1736

- 2y + 6.8y = 1736 - 776

4.8y = 960

y = 960/4.8

y = 200

x = 388 - y = 388 - 200

x = 188

4 0

2 years ago