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3 years ago

7

1 lakh more then 45,25,306

1 answer:

kakasveta [241]3 years ago

3 0

Answer:

your answer will be 46 ,25,306

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Ali finished his history assignment in 1/4

Juli2301 [7.4K]

$\frac{1}{4} \times 3 = \frac{3}{12} \frac{2}{3} \times 4 = \frac{8}{12} \\ \frac{3}{12} + \frac{8}{12} = \frac{11}{12}$

5 0

4 years ago

there are 120 seats in the balcony of theatre .if this 1/5 of the total seats, what's the total number of seats in the theater

natka813 [3]

Answer:

600 seats

Step-by-step explanation:

We know there is 120 seats on a balcony and that is $\frac{1}{5}$ of the total seats, we want to find the total number of seats so,

120 seats = $\frac{1}{5}$

We know that a whole fraction sums to 1 so for example $\frac{1}{5} +\frac{4}{5} =\frac{5}{5} =1$

120 seats = $\frac{1}{5}$

Multiply both sides to make it a whole fraction

600 seats = $\frac{5}{5} =1$

So if there is 120 seats and that number is only $\frac{1}{5}$ of the total number of seats then the total number of seats is 600

3 0

3 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Write an equation in slope-intercept form for the line with slope 1/4 and y intercept -4. Then graph the line

quester [9]

Answer:

Step-by-step explanation:

slope intercept form is y = mx + b

b is the y intercept ( crossing y axis value).... by inspection b = -4

m is the slope of the line, Slope = m = 1/4 note: the slope is positive

the slope equals the 'rise' over 'run'

if the line moves up the slope is positive, if the line moves down the slope is negative

the rise is how many y units does the line go 'up' or 'down'

the run is how many x units does the line go 'left' or 'right'

the rise = 1 Y unit

the run = 4 X units

y = mx + b m =1/4 b = -4

y = (1/4)x + (-4)

y = (1/4)x - 4

graph a line stating at y = -4 and going up (rising) to the right ONE Y Unit for every FOUR X units (the run)

3 0

3 years ago

The blade length is the radius of the circle formed by the area swept by the blades to the nearest square foot, what is the area

rewona [7]

Sorry i do not know wish i did

3 0

3 years ago

Read 2 more answers