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2 years ago

Which expression is equivalent to (8^2)-4 ??

Mathematics

2 answers:

Veronika [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Tamiku [17]2 years ago

3 0

Answer:

Option C $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

we have

$(8^{2})^{-4}$

Remember that

$(a)^{-b} = \frac{1}{a^{b}}$

$(a^{b})^{c}=(a)^{b*c}$

therefore

$(8^{2})^{-4}=(8)^{-4*2}=(8)^{-8}$

$(8)^{-8} = \frac{1}{8^{8}}$

$\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$

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3 years ago

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3 years ago

The diagram shows a right-angled triangle. a 12 cm 24 cm Find the size of angle x.

Vlada [557]

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2 years ago

the scale on the map is 1 cm : 80 km . if two cities are 4 cm apart on the map, what is the actual distance between the cities?

jarptica [38.1K]

Hello there! Your answer would be 'the actual distance between the cities is 320 kilometers'.

Okay, so to solve this, we can use unit rates. We know that for every one centimeter we have eighty kilometers. So, whatever we multiply the centimeter value by, we can multiply the kilometer value by the same number and get our answer.

So if the centimeter value is 4, multiply the kilometer value by 4.

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3 years ago

Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade

Archy [21]

The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$