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2 years ago

Which expression is equivalent to (8^2)-4 ??

Mathematics

2 answers:

Veronika [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Tamiku [17]2 years ago

3 0

Answer:

Option C $\frac{1}{8*8*8*8*8*8*8*8}$

Step-by-step explanation:

we have

$(8^{2})^{-4}$

Remember that

$(a)^{-b} = \frac{1}{a^{b}}$

$(a^{b})^{c}=(a)^{b*c}$

therefore

$(8^{2})^{-4}=(8)^{-4*2}=(8)^{-8}$

$(8)^{-8} = \frac{1}{8^{8}}$

$\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}$

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. You work at a department store and make $9 per hour plus 12% commission

Luda [366]

Start with hours worked 6 x $9 = 54
Then commission $700 x 0.12 (12% converted to a decimal) = $84
Add up 54 + 84 = $138 total income

So answers are A, the first C (you make $84 in commission), and the last one, you make $138 in total.

5 0

2 years ago

Evaluate z^2−3 z+4 , when z=−4

Maru [420]

Answer:

Step-by-step explanation:

=z²-3z+4 when z is 4

=4²-3(4)+4

=16-12+4

6 0

2 years ago

Read 2 more answers

Simplify and explain how you got the answer:

timama [110]

Answer:

The answer is A

Step-by-step explanation: look at the picture for explanation

5 0

2 years ago

According to the U.S. Bureau of the Census, the average age of brides marrying for the first time is 23.9 years with a populatio

JulsSmile [24]

Answer:

We conclude that young women are delaying marriage and marrying at a later age.

Step-by-step explanation:

We are given that the average age of brides marrying for the first time is 23.9 years with a population standard deviation of 4.2 years.

The sociologist randomly samples 100 marriage records and determines the average age of the first time brides is 24.9 years.

Let $\mu$ = average age of brides marrying for the first time.

So, Null Hypothesis, $H_0$ : $\mu$ = 23.9 years {means that young women are not delaying marriage and marrying at a later age}

Alternate Hypothesis, $H_A$ : $\mu$ > 23.9 years {means that young women are delaying marriage and marrying at a later age}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age of the first time brides = 24.9 years

$\sigma$ = population standard deviation = 4.2 years

n = sample of marriage records = 100

So, the test statistics = $\frac{24.9-23.9}{\frac{4.2}{\sqrt{100} } }$

= 2.381

The value of z test statistics is 2.381.

Now, at 1% significance level the z table gives critical value of and 2.326 for right-tailed test.

Since our test statistic is more than the critical value of z as 2.381 > 2.326, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that young women are delaying marriage and marrying at a later age.

5 0

2 years ago

A plane flies 450 miles with the wind, and 350 miles against the wind (in the same amount of time). If the wind is blowing at 30

adell [148]

Answer: = 240 mph.

Step-by-step explanation:

Let x = speed of the plane.

t= time taken

As per given, we have

$t=\dfrac{450}{x+30}\ \ \ ...(i)\\\\ t=\dfrac{350}{x-30}\ \ \ ...(ii)$ [Time = distance / speed]

From (i) and (ii), we get

$\dfrac{450}{x+30}=\dfrac{350}{x-30}\\\\\Rightarrow\ 450(x-30)=350(x+30)\\\\\Rightarrow\ 450x-13500=350x+10500\\\\\Rightarrow\ 450x-350x=10500+13500\\\\\Rightarrow\ 100x=24000\\\\\Rightarrow\ x=240$

Hence, the speed of the plane = 240 mph.

7 0

2 years ago