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garik1379 [7]
3 years ago
13

Deal A is at Walmart and they are selling 50 cupcakes for $30 dollars but gives you 10% discount. Deal B is at Costco gives you

50 percent more cupcakes at the same price at $30 of but no discount. which is a better deal.
Mathematics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

Deal B

Step-by-step explanation:

Deal A : $ 30 *10%=3 dollars

the price for 50 cupcake is 27 dollars (54 cent for one cupcake)

Deal B: 50*50%= 25 more cupcake

75 cupcake for 30 dollars ( 40 cents per cupcake)

Deal B is better than Deal A

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Eight people are equally sharing 12 muffins. How many muffins will each person receive?
Marina CMI [18]
Total number of muffins = 12 muffins
Total number of people sharing muffin = 8

Muffins each person will receive = Total number of muffins
                                                          ---------------------------------
                                                          People sharing muffins
                                                   
                                                    = 12/8
                                                    = 1 1/2  OR  1.5 muffins



7 0
3 years ago
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Help me pls pls pls pls pls
Oxana [17]

Answer:

B.x>4is a required interval.

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3 years ago
39. Rewrite each expression as an equivalent expression containing only one logarithm.
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Answer:

ln{\frac{(p+q)^3}{q^2p^7} }

Step-by-step explanation:

3 ln(p + q) − 2 ln(q) − 7 ln(p)

=ln(p+q)^3- ln(q)^2-ln(p)^7

= ln(p+q)^3-{ln(q)^2+ln(p)^7}

=ln(p+q)^3-ln(q)^2*(p)^7

=ln{ (p+q)^3÷(q)^2*(p)^7}

=ln{\frac{(p+q)^3}{q^2p^7} }

3 0
3 years ago
All repeating decimals are irrational True or false
egoroff_w [7]

Answer:

Step-by-step explanation: true

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3 years ago
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How to work it out logically? Question a !!!
Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

                          =L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha

Area of region 2 = ar(DHBC)

                       =2000\times1500\\\\=3000000m^2=300ha

Area of region 3 = ar(GFEH)

                             (2000+1500)\times 1000\\\\=3500000m^2=350ha

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

                                                 =987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

7 0
3 years ago
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