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WITCHER [35]
3 years ago
14

In genetic diseases like Down syndrome, the cause is often due to the presence of an extra chromosome. Do you think this mutatio

n would occur in meiosis or mitosis? Why?
Biology
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

The mutation observed in the down syndrome occurred as a result of a abnormal and non disjuncted meiosis.

Explanation:

Howbeit, mutation can be described as any heritable change of the base-pair sequence of genetic material.

Down syndrome also described as trisomy 21 is a medical condition caused by a chromosomal excess, whereby the patients bear a certain resemblance to the Mongoloid race, such as a small head and tilted eyelids, and typically have a delay in cognitive ability and physical growth.

Meiosis is one that describes the cell division process of a diploid cell into four haploid cells, which develop to produce gametes.

The chromosomal mutation of nondisjunction in down syndrome describes how a pair of chromosomes is not fully separated during meiosis, resulting in the gamete having an extra chromosame (or none at all).

.

grigory [225]3 years ago
4 0

Answer:

meiosis

Explanation:

Down syndrome is an abnormality that occurs on chromosomes 21, it occurs because chromosomes 21 cannot be separated in meiosis, the pair of chromosomes 21 do not separate and go together to one of the daughter cells. In this way, the oocyte or the resulting sperm will have 24 chromosomes instead of 23. When in conception that oocyte or sperm joins the germ cell of its partner that contributes the 23 chromosomes, the total sum of chromosomes that will have the first cell of the new conceived being will be 47.

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7 0
3 years ago
What is meant by “concentration”? How can you increase the concentration of salt (electrolytes) in a solution of water? How can
GuDViN [60]

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3 0
3 years ago
A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

5 0
3 years ago
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