We are given the relation between the height (in feet) and the distance (in miles) as follows:
y = sqrt(1.5x + (x/5280)^2).
We want to know the height (x) that makes the distance (y) = 10 miles
So, we will simply substitute in the above equation with y = 10 and calculate x as follows:
10 = sqrt(1.5x + (x/5280)^2)
we will square both sides to get rid of the root:
100 = 1.5x + (x/5280)^2
1.5x + (x/5280)^2 - 100 = 0
(x-66.11475)(x+7986.1147) = zero
either x = 66.11475 feet (accepted solution)
or x = -7986.1147 feet (rejected solution as no height is in negative)
Answer:

Step-by-step explanation:
<u>Given equation is:</u>

Multiply 2 to 4

While comparing both sides, we get:
7 = n
OR
n = 7
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Set s(t) = 0 which means it hits the ground. The formula doesn't fit the parameters given as it shows that the pitcher is standing on something 37 feet high.
<span>s(t)=-16t^2+140t+37 and has an initial velocity of 140.
Graphing or solving this, t= 9 seconds when it hits the ground.
The velocity V(t) is the derivative of s(t)
V(t) = -32t+140
V(9) = -148 ft/second which is going down
</span>
Line b and h because to find radius it half of the diameter of STRAIGHT lines
Answer:
A
Step-by-step explanation:
12/4=3
20/4=5