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RideAnS [48]
3 years ago
13

A single die is rolled, find the probability that the number is even or less than 6

Mathematics
1 answer:
stepladder [879]3 years ago
8 0
1/1 chance, since 2,4,6 is even, and all numbers are less than 6 except 6, but since you said or, it doesn't matter because 6 is still even despite being not less than 6.
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Y decreased by 9is 8
olga55 [171]

Answer:

It's easy to figure it out. The equation we have is 8 = y - 9. We need to isolate y. Simply add 9 to each side of the equation to get this: 17 = y.

ANSWER: 17 = y

8 0
3 years ago
What’s the Answer of this question plz? The total
ryzh [129]

Answer:

I think it's six

Step-by-step explanation:

A= 1

b= 2

c= 3

4 0
3 years ago
Tamara makes 12 identical flower arrangements, each with 3 roses and some carnations. She uses a total of 96 flowers.
storchak [24]

Answer:

5 carnations in each arrangement

Total of 60 carnations used

Step-by-step explanation:

First calculate how many flowers are in each arrangement by dividing the total number of flowers by the number of arrangements:

96 ÷ 12 = 8

Given each arrangement has 3 roses, subtract 3 from 8 to find the number of carnations in each arrangement:

8 - 3 = 5

Therefore, there are 5 carnations in each arrangement

Total number of carnations used = 5 x 12 = 60

5 0
2 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
PLEASE HELP QUESTION: What is the midpoint of the line containing the points X(4,-1) and Y(-4,1)?
11Alexandr11 [23.1K]

Answer:

( D ) , ( 0 , 0 )

6 0
3 years ago
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