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4 years ago

13

What is (x) in this problem 3/5=(-x)+1

1 answer:

Maurinko [17]4 years ago

3 0

3/5= -x+1
-2/5= -x

x = 2/5

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What is 1 11/12-1 7/12=

kow [346]

The answer for your problem is 1/3

4 0

3 years ago

What is the surface area of the prism in square inches?

Snowcat [4.5K]

Answer:

176

Step-by-step explanation:

You multiply the length by the width to know the area or a square/rectangle (2D), so you multiply length by width by height to know the volume of a prism (3D). so 11*2"8=176

7 0

3 years ago

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Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?

mixer [17]

Given:

$|u|=10$ at an angle of 45°.

$|v|=13$ at an angle of 150°.

$w=u+v$

To find:

Magnitude and direction angle of w.

Solution:

We have,

$w=u+v$

$\theta = 45^\circ, \phi = 150^\circ$

Now,

$u_x=|u|\cos \theta=10\cos 45^\circ=7.071$

$u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071$

$v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833$

$v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5$

Using these information, we get

$R_x=u_x+v_x=7.071-11.25833=-4.18733$

$R_y=u_y+v_y=7.071+6.5=13.571$

$\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})$

$\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})$

$\text{Direction angle}=-72.8239$

$\text{Direction angle}=107.1476$

$\text{Direction angle}\approx 107.1$

Now,

$|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}$

$|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}$

$|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}$

$|w|=14.20236$

$|w|\approx 14.20236$

Therefore, the correct option is D.

4 0

3 years ago

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Which of the following equations is modeled by the graph

Stels [109]

B is the correct answer.

4 0

3 years ago

HELP ME ASAP PLEASE!!!!

vesna_86 [32]

Answer:

D good luck

Step-by-step explanation:

6 0

3 years ago