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vovikov84 [41]
3 years ago
6

What is the solutions to 0=x^2-x-6 two things ,,quadratic equationz,,,

Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

x1=3. x2=-2

Step-by-step explanation:

x =  \frac{ - b +  -  \sqrt{b {}^{2} - 4ac } }{2a}

b=-1

a=1

c=-6

x =  \frac{ - ( - 1) +  -  \sqrt{ {( - 1)}^{2} - 4 \times 1 \times ( - 6) } }{2 \times 1}

x =  \frac{1 +  -  \sqrt{1 + 24} }{2}

x =  \frac{1 + -   \sqrt{25} }{2}

x1 =  \frac{1 + 5}{2}

x2 =  \frac{1 - 5}{2}

x1=3

x2=-2

x =  \frac{1 +  - 5}{2}

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Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul
sesenic [268]

The expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,


C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}


now put the value in the formula.

5 = \sqrt{(x-6^2)+(y - 5)^2}

Thus, expression      5 = \sqrt{(x-6^2)+(y - 5)^2}  can be used to find the coordinate of Point B. Option C is correct.


Learn more about equation here:

brainly.com/question/10413253

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4 0
1 year ago
HELP ME PLEASE ASAP
Paha777 [63]

Answer:

33

Step-by-step explanation:

angles on a straight line sum up to 180°

104+x+x+10=180

114+2x=180

2x=180-114

2x=66

x=33

3 0
3 years ago
Read 2 more answers
Pls help!!!!!!!!!!!!!!!!​
Mariulka [41]

Answer:

f(2) = 75

f(6) = 4091

Step-by-step explanation:

5 0
3 years ago
State whether the following coordinates on a Cartesian plane form an acute, obtuse or right triangle: a) (-1, 1), (7,-2) and (1,
LiRa [457]

Answer:

a) Acute triangle

b) Right triangle

Step-by-step explanation:

∵ A triangle having sides a, b and c is called,

Acute : If a² + b² > c² or a² + c² > b² or b² + c² > a²,

Obtuse : if a² + b² < c² or a² + c² < b² or b² + c² < a²

Right : a² + b² = c² or a² + c² = b² or b² + c² = a²,

a) Let A≡(-1, 1), B≡(7,-2) and C≡(1,-5),

By the distance formula,

AB=\sqrt{(7-(-1))^2+(-2-1)^2}=\sqrt{(7+1)^2+(-3)^2}=\sqrt{8^2+3^2}=\sqrt{64+9}=\sqrt{73}\text{ unit}

Similarly,

BC=\sqrt{45}\text{ unit}

CA=\sqrt{40}\text{ unit}

∵ The sum of any two sides is greater than third side,

So, ABC is a triangle,

Now,

AB^2 + BC^2 > CA^2

⇒ ABC is an acute triangle.

b) Let P≡(0,6), Q≡(1,2) and R≡(5,3),

By the distance formula,

PQ = √17 unit,

QR = √17 unit,

RP = √34 unit,

∵ The sum of any two sides of PQR is greater than third side,

⇒ PQR is a triangle ,

Also,

RP^2=PQ^2+QR^2

Hence, PQR is a right triangle.

3 0
3 years ago
The defective rate for phone charges is 1.5% the store manager orderd 250 how many did he order
timofeeve [1]

Answer:

if you did the math 3.75 came up but you can't have 3 quarters of a phone so the answer should be the store manager ordered 3 defective phones


7 0
3 years ago
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