Answer: Look at the variables (letters) and plug them in
Step-by-step explanation: You plug in the variables into the problem, then you separate the other variable that you don't know from your whole number by bringing it to the other side. Then you can divide or whatever you have to do.
Answer: 12
Step-by-step explanation:
this is a right angled triangle so you use the pythagorean theory
which is a^2 + b^2 = c^2
you have c and b already. c is the hypotenuse.
a^2 + 16^2 = 20^2
a^2 + 256 = 400
a^2 = 400 - 256
a^2 = 144
then you square root 144 and get..
a = 12
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.
The area of a triangle with vertices known is given by the matrix
M =
Area = 1/2· | det(M) |
= 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
= 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |
Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
= 1/2· | -5·(1) - 4·(-13) - 1·(12) |
= 1/2 | 35 |
= 35/2
Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
= 1/2· | -5·(11) + 4·(-13) - 1·(2) |
= 1/2 | -109 |
<span> = 109/2</span>
The total area of the quadrilateral will be the sum of the areas of the two triangles:
A(ABCD) = A(ABC) + A(ADC)
= 35/2 + 109/2
= 72
Solution:
Given :
- Area of triangle = 10 ft²
- Height of triangle = 10 ft
So, We have to find the Base of Triangle .
Area of triangle = 1/2*b×h, Where represents
- B represent Base
- H represent Height
Step : Substitute those value in Formula;
Area of triangle = 1/2 × b × h
10 = 1/2 × b × 11
20 = 11 × b
b = 20/11
b = 1.81 ft
Therefore, Base of Triangle is 1.81 ft
I think 289 x 3.14 which is 907.46 m2
So the answer should be = 907.46 meter square
Hope its help