The value of a particular trigonometric expression that is cos 2θ under the third quadrant is -119/169
Given:
sin θ = -⁵/₁₃
This can be seen from the trigonometric identity.
cos 2θ = 1 - 2sin²θ
From trigonometric identities, we know that;
cos 2θ = 1 - 2sin²θ
Thus;
cos 2θ = 1 - 2(-⁵/₁₃)²
cos 2θ = 1 - 2(25/169)
cos 2θ = 119/169
since cos θ is negative in the third quadrant, then we have;
cos 2θ = -119/169
so; cos θ is negative in the third quadrant, so ;
cos 2θ = -119/169
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Line D and C shows direct variation because the line goes through the origin my good sir or ma'am :)
Answer:
102.5
Step-by-step explanation:
Step-by-step explanation:
I have no idea if I'm doing it right but my guess would be to take the values that we get from f(x) and g(x) when x = 1. Therefore we get that f(x) is equal to 4 and g(x) is equal to -1. We than just do f/g which is 4/-1 which gives us the final answer of -4 which is option B.
Answer: Option B, -4
