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vagabundo [1.1K]

3 years ago

9

Find the inverse of g(x)

1 answer:

borishaifa [10]3 years ago

5 0

To find the inverse of function f(x), follow these steps.
1) Replace f(x) with y.
2) Switch x and y.
3) Solve for y.
4) Replace y with f^(-1)(x).

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Write an equation <br><br> 1) y=3<br> 2) y=3/4+3<br> 3) y=3/4x+3<br> 4) y=4

lianna [129]

Answer:

It B

Step-by-step explanation:

This is because the y-intercept is 3 and it going down

Hope this Helped

8 0

3 years ago

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Please help!!!! And show work please!

marin [14]

C. Table T
It is not a function if one x value gives more than 1 y-value. In table T, 3 gives 4 and -4 two different y values.

7 0

2 years ago

How do I graph y=-3/2x+3

Goshia [24]

Answer

Start at 3 (y) go down 3 and over 2 to the right

Step-by-step explanation:

4 0

3 years ago

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The distance from Josh's house to the mall is 3.5 miles. The distance from Meg's house to the mall is 19,000 feet. Who lives clo

GalinKa [24]

Answer:

12

Step-by-step explanation:

7 0

3 years ago