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3 years ago

I urgently neeed number 4 plzzzzzzz ASP

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

Answer: Noah is right. If the mean for the second lake is 60ft and the first lake is 45ft, the second lake has an average depth that is 15 feet deeper.

The standard deviations also indicate that the second lake has some even deeper spots, and even the shallower spots of the second lake are about the same as the shallow spots of the first lake.

Step-by-step explanation:

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Write an equation of the line with a slope of 34 and a y-intercept of −2

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Wouldn’t it be? Y=34x-2

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3 years ago

Solve for f. -f + 2 + 4f = 8 - 3 f=

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Answer:

Step-by-step explanation:

-f + 2 + 4f = 8 - 3

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A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

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3 years ago

What set of reflections would carry parallelogram ABCD onto itself?

My name is Ann [436]

"y-axis, x-axis, y-axis, x-axis" is the set of reflections among the following choices given in the question that would carry parallelogram ABCD onto itself. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has helped you.

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