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Pachacha [2.7K]
4 years ago
8

Solve the equation and state the value of xw - 2 = -8- 5w​

Mathematics
1 answer:
Wewaii [24]4 years ago
4 0

Answer:

x=-1

Step-by-step explanation:

w-2=-8-5w

-2=-8-6w

+8 +8

6=-6w

divide 6 in both side

x=-1

hope this help.

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Convert the measurement as indicated.
grigory [225]

Answer:

7 gal 3 qt is 31 quarts.

Step-by-step explanation:

Given:

7 gal 3 qt to quarts.

Now, convert the measurement as indicated.

So, the value of 1 gallon = 4 quarts.

Thus , the 7 gal(gallons) = 7 × 4 = 28 quarts.

And 3 qt (quarts) = 3 × 1 = 3 quarts.

So,

7\ gal\ 3\ qt

=28 quarts+3 quarts

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6 0
3 years ago
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-(1/2)p<-16

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Félix grew 8 flowers with 2 seed packets. With 5 seed packets, how many total flowers can Felix have in his garden? Solve using
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Answer:

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Step-by-step explanation:

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An above-ground swimming pool in the shape of a cylinder has a diameter of
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18-6=12

4.5 the finest in a wide range is to make the best choice of

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3 years ago
The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college
hammer [34]

Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

6 0
3 years ago
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