The internet has provided great opportunities for fundraising. true/false

On a network, which protocol is responsible for dividing files into chunks, adding headers containing information for reassembli

andrew11 [14]

Answer:

TCP

Explanation:

TCP (Transmission Control Protocol) is a standard that defines how to establish and maintain a network conversation through which application programs can exchange data. TCP works with the Internet Protocol (IP), which defines how computers send packets of data to each other.

4 0

2 years ago

Take the average of some numbers. Show all the numbers that are below average. You can assume that there will not be more than 2

olchik [2.2K]

Here is code in java.

import java.util.*; // import package

class Main // creating class

{

public static void main (String[] args) // main method

{

Scanner br=new Scanner(System.in); // scanner class for input

int []a=new int[20]; // declaring array

int count=0,x,j; // creating variable

int sum =0;

System.out.println("Enter a weight (0 to stop):");

x=br.nextInt(); // taking input

while(x!=0) // iterating over the loop

{

a[count] = x;

count++;

System.out.println("Enter a weight (0 to stop):");

x=br.nextInt();

}

for( j=0;j<count;j++) // iterating over the loop

{

sum+=a[j];

}

double avg = sum/(double)count;

System.out.println("The total is: "+sum);

System.out.println("The average is: "+avg);

System.out.println("Here are all the numbers less than the average: ");

for( j=0;j<count;j++) // // iterating over the loop

{

if(a[j]<avg)

System.out.print(a[j]+" ");

}

Explanation:

First create an object of "Scanner" class to read input from the user.

Create an array of size 20, which store the number given by user.Ask user

to give input and keep the count of number in the variable "count". If user

give input 0 then it will stop taking input.And then calculate sum of all the

input.It will calculate average by dividing the sum with count and print it.

It will compare the all elements of array with average value, if the element

is less than average, it will print that element.

Output:

Enter a weight (0 to stop):

1

Enter a weight (0 to stop):

2

Enter a weight (0 to stop):

3

Enter a weight (0 to stop):

4

Enter a weight (0 to stop):

5

Enter a weight (0 to stop):

6

Enter a weight (0 to stop):

7

Enter a weight (0 to stop):

8

Enter a weight (0 to stop):

9

Enter a weight (0 to stop):

10

Enter a weight (0 to stop):

0

The total is: 55

The average is: 5.5

Here are all the numbers less than the average:

1 2 3 4 5

6 0

3 years ago

Program 7 - Circle You write ALL the code, then run it - Produce the correct output. Turn in code and screen print of successful

fgiga [73]

Answer:

Here is the Circle class:

public class Circle { // class definition

private int radius; // private data member of type int of class Circle named radius that stores the value of radius

public Circle(int r) { // parameterized constructor of class Circle that takes radius as argument

radius = r; } // sets value of radius as r

public int getRadius() { // accessor method to get the value of radius

return radius; } // returns the current value of radius

public int Diameter() { // method to compute diameter of a circle

return radius * 2; } // multiply radius value by 2 to compute diameter of Circle

public double Area() { // method to compute area of a circle

return Math.PI * Math.pow(radius, 2); } //the formula of area is

π x radius² where value of π is get using Math.PI

public double Circumference() { // // method to compute circumference of a circle

return 2* Math.PI * radius; } } //the formula of circumference is

2 x π x radius where value of π is get using Math.PI

Explanation:

Here is the Main class:

import java.util.Scanner; //to accept input from user

public class Main { //definition of Main class

public static void main(String[] args) { //start of main method

Scanner scanner = new Scanner (System.in); //creates Scanner object to take input from user

System.out.println("Enter radius: "); //prompts user to enter radius

int r = scanner.nextInt(); //reads the value of radius from user

Circle c = new Circle(r); // calls Constructor of Circle passing r as argument to it using the object c of class Circle

if(c.getRadius()<=0){ //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0

System.out.println("Error!"); } //when above if condition evaluates to true then print this Error! message

else { //if the value of radius is greater than 0

System.out.println("the radius of this Circle is: " +c.getRadius()); //calls getRadius method to return current value of r (input value by user)

System.out.println("the diameter of this Circle is: " + c.Diameter()); //calls Diameter method to compute the diameter of Circle and display the result on output screen

System.out.printf("the circumference of this Circle is: %.2f", c.Circumference()); //calls Circumference method to compute the Circumference of Circle and display the result on output screen

System.out.println(); //prints a line

System.out.printf("the Area of this Circle is: %.2f", c.Area()); } } }

//calls Area method to compute the Area of Circle and display the result on output screen

The program and its output is attached.

7 0

3 years ago

All of the following are the four more widely social media networks discussed in the text EXCEPT:

Elan Coil [88]

The answer is E) Groupon

8 0

3 years ago

Read 2 more answers

An internal conflict is generally harder to write and still harder to convey in an interactive computer game

Tanya [424]

True, because of how the human mind works, you could have a fairly hard decision that could affect your life. So, An Internal conflict is more difficult to convey in an interactive computer game.

7 0

3 years ago