The internet has provided great opportunities for fundraising. true/false

You are given two variables, already declared and assigned values, one of type double, named price, containing the price of an o

Oksi-84 [34.3K]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

//variable to store input

double price;

int totalNumber;

// variable to store total price

double total_price;

cout<<"Enter the price of an order:";

// read the price of an order

cin>>price;

cout<<"Enter the number of orders:";

// read the total number of orders

cin>>totalNumber;

// calculate total price of all orders

total_price=price*totalNumber;

cout<<"total price of all orders: "<<total_price<<endl;

return 0;

}

Explanation:

Declare three variables "price" of double type,"totalNumber" of int type And "total_price" of type double.Read the value of an order and number of orders. The calculate the total price by multiply "price" with "totalNumber" and assign it to variable "total_price". Print the total price.

Output:

Enter the price of an order:12.5

Enter the number of orders:3

total price of all orders: 37.5

7 0

4 years ago

Consider the following code segment. int[][] arr = {{3, 2, 1}, {4, 3, 5}}; for (int row = 0; row < arr.length; row++) { for (

ludmilkaskok [199]

Answer:

Condition one - 1 time

Condition two - 2 times

Explanation:

Given

The above code segment

Required

Determine the number of times each print statement is executed

For condition one:

The if condition required to print the statement is: if (arr[row][col] >= arr[row][col - 1])

For the given data array, this condition is true only once, when

$row = 1$ and $col = 2$

i.e.

if(arr[row][col] >= arr[row][col - 1])

=> arr[1][2] >= arr[1][2 - 1]

=> arr[1][2] >= arr[1][1]

=> 5 >= 3 ---- True

The statement is false for other elements of the array

Hence, Condition one is printed once

For condition two:

The if condition required to print the statement is: if (arr[row][col] % 2 == 0)

The condition checks if the array element is divisible by 2.

For the given data array, this condition is true only two times, when

$row = 0$ and $col = 1$

$row = 1$ and $col = 0$

i.e.

if (arr[row][col] % 2 == 0)

When $row = 0$ and $col = 1$

=>arr[0][1] % 2 == 0

=>2 % 2 == 0 --- True

When $row = 1$ and $col = 0$

=>arr[1][0] % 2 == 0

=> 4 % 2 == 0 --- True

The statement is false for other elements of the array

Hence, Condition two is printed twice

3 0

3 years ago

What are the programming concepts (within or outside the scope of IT210) that you would like to strengthen and delve into furthe

marin [14]

Answer:

The description for the given question is described in the explanation section below.

Explanation:

I would like to reinforce in advanced or complex concepts such as documents as well as channels, internet programming, multi-threading, after that last lesson.

I am interested in learning web development to develop applications or software. I would also like to explore those concepts by using open source tools.
Course concepts will have to develop models for handling.
No there is no subject matter or definition you provide further clarity for.
I'm interested in studying java as well as web development in comparison to C++ so I can use it in my contract work.

4 0

3 years ago

1. Write a program to prompt the user to enter a single character and respond back whether or not the character is valid dna. 2.

Nina [5.8K]

Answer:

Answer 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

print("valid")

else:

print("invalid")

Answer 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

print("valid")

else:

print("invalid")

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

if char not in ["A", "C", "G", "T"]:

type = "invalid"

break

print(type)

Answer 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

if char not in ["A", "C", "G", "U"]:

type = "invalid"

break

print("valid")

Explanation:

There are three types of DNA; Type A, Type B and Type Z.

A DNA sequence consists of; A, C, G and T.

There are three types of RNA; mRNA, tRNA and rRNA.

An RNA sequence consists of; A, C, G and U.

Code Explanations:

Code 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

print("valid")

else:

print("invalid")

prompts and Takes a single character input
converts the character to upper case
compares the input to the DNA types
Prints "valid" for a valid input else prints "invalid"

Code 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

print("valid")

else:

print("invalid")

prompts and Takes a single character input
converts the character to lower case
compares the input to the RNA types
Prints "valid" for a valid input else prints "invalid"

Code 3:

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

if char not in ["A", "C", "G", "T"]:

type = "invalid"

break

print(type)

It prompts for a DNA sequence.
Declares a string variable "type" and initializes type to valid.
The FOR loop checks every character in the DNA sequence.
If the character is not in the list [A, C, G, T] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
if all the characters are in the list, then type will remain valid and will be printed to the screen.

Code 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

if char not in ["A", "C", "G", "U"]:

type = "invalid"

break

print("valid")

It prompts for a RNA sequence.
Declares a string variable "type" and initializes type to valid.
The FOR loop checks every character in the RNA sequence.
If the character is not in the list [A, C, G, U] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
if all the characters are in the list, then type will remain valid and will be printed to the screen.

7 0

3 years ago

The memory management layer is the part of the kernel that serves out all memory allocation requests.

svetlana [45]

Most likely it’s False . But look it up just in case

4 0

3 years ago