Question

Perform the indicated operation. (6f^2 - 13 - 11f) ÷ (3f - 4)

Answer 1

Answer:

$2f - 1 +\frac{-10}{3f-4}$

Step-by-step explanation:

Given :- $\frac{6f^{2}-13-11f}{3f-4}$

We perform this operation by long division method which is shown in figure-1

steps as follows:

1) we multiply 3f-4  by 2f and get 6f² -8 and then

2) subtract 6f² -8 from 6f² - 13 -11f ,we we get -3f - 13

3) now multiply 3f-4  by -1 and get -3f - 13

4) subtract -3f -3 from -3f -13 ,we we get -10

where dividend is 6f² - 13 -11f, divisor is 3f-4, Quotient is 2f - 1 and remainder is -10.

$2f - 1 +\frac{-10}{3f-4}$

Answer 2

                  2f -    1
3f - 4|6f² - 11f - 13
      - (6f² -  8f)
                 -3f - 13
              - (-3f -  3)
                        -10

$It\ is\ equal\ to\ 2f - 1 + \frac{-10}{3f - 4}.$