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3 years ago

I dont know how to eat fries how to eat fries

Business

2 answers:

Ierofanga [76]3 years ago

8 0

Answer:

use ur head

Explanation:

grab a frie with any hand, left or right. Then, you have a choice whether to dip it in a sauce idk. next, put in your mouth and chew it and swallow it. ur wlecome.

Follow me

xo.br0ken

intsa

sasho [114]3 years ago

4 0

Answer:

Just put the fries in your mouth then start chewing mostly prefered dipped in ketchup.

Explanation:

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Your portfolio is invested 30 percent each in Stocks A and C, and 40 percent in Stock B. What is the standard deviation of your

Assoli18 [71]

Answer:

portfolio's standard deviation = 6.18%

Explanation:

we must first determine the expected returns for each stock:

stock A = (0.15 x 31%) + (0.6 x 16%) + (0.2 x -3%) + (0.05 x -11%) = 13.1%

stock B = (0.15 x 41%) + (0.6 x 12%) + (0.2 x -6%) + (0.05 x -16%) = 11.35%

stock C = (0.15 x 21%) + (0.6 x 10%) + (0.2 x -4%) + (0.05 x -8%) = 7.95%

then we must determine the variance of each stock's return:

stock A = {[0.15 x (31 - 13.1)²] + [0.6 x (16 - 13.1)²] + [0.2 x (-3- 13.1)²] + [0.05 x (-11 - 13.1)²]} / 4 = (48.0615 + 5.046 + 51.842 + 29.0405) / 4 = 33.4975

stock B = {[0.15 x (41 - 11.35)²] + [0.6 x (12 - 11.35)²] + [0.2 x (-6- 11.35)²] + [0.05 x (-16 - 11.35)²]} / 4 = (131.868375 + 0.2535 + 60.2045 + 37.401125) / 4 = 57.4219

stock C = {[0.15 x (21 - 7.95)²] + [0.6 x (10 - 7.95)²] + [0.2 x (-4- 7.95)²] + [0.05 x (-8 - 7.95)²]} / 4 = (25.545375 + 2.5215 + 28.5605 + 12.720125) / 4 = 17.3369

portfolio's variance = (0.3 x 33.4975) + (0.4 x 57.4219) + (0.3 x 17.3369) = 38.21908

portfolio's standard deviation = √38.21908 = 6.18%

5 0

2 years ago

Imagine that odyssey national is a brand new bank, and that its required reserve ratio is 10 percent. if it accepts a $1,000 dep

Snezhnost [94]

Hi there
Excess reserve balance is
1,000−1,000×0.1=900

Hope it helps

8 0

3 years ago

Read 2 more answers

You want a new cell phone. Which of these sources would be the most dependable?

ahrayia [7]

I would say that b is the best answer

3 0

3 years ago

Read 2 more answers

Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma

Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so the maximizing function is the profit function which is given as

$P=90X+120Y+150Z$

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

$2X+2Y+Z\leq 400$

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

$3X+4Y+6Z\leq 240$

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

$4X+6Y+5Z\leq 320$

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{2X+2Y+Z}{40}\leq 10$

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{3X+4Y+6Z}{40}\leq 6$

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

$\dfrac{4X+6Y+5Z}{40}\leq 8$

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

$\dfrac{2X+2Y+Z}{35}$

That of machine 2 is given as

$\dfrac{3X+4Y+6Z}{35}$

That of machine 3 is given as

$\dfrac{4X+6Y+5Z}{35}$

As the total number of workers is 19 so the constraint is given as

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

So the Linear programming model is given as below

Profit Function: $P=90X+120Y+150Z$

Constraints:

$2X+2Y+Z\leq 400$

$3X+4Y+6Z\leq 240$

$4X+6Y+5Z\leq 320$

$\dfrac{2X+2Y+Z}{40}\leq 10$

$\dfrac{3X+4Y+6Z}{40}\leq 6$

$\dfrac{4X+6Y+5Z}{40}\leq 8$

$\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19$

4 0

3 years ago

On April 1, 2021, Shoemaker Corporation realizes that one of its main suppliers is having difficulty meeting delivery schedules,

Vlad [161]

Answer:

Explanation:

The journal entries are shown below:

1. Notes receivable A/c Dr $450,000

To Cash A/c $450,000

(Being the notes receivable acceptance is recorded)

2. Interest receivable A/c Dr $40,500

To Interest revenue $40,500

(Being the interest is collected)

Interest = Principal × rate of interest × number of months ÷ (total number of months in a year)

= $450,000 × 12% × (9 months ÷ 12 months)

= $40,500

The 3 months is calculated from April 1 to December 31

3. Cash A/c Dr $504,000

To Notes receivable A/c $450,000

To Interest receivable A/c $40,500

To Interest revenue A/c $13,500

(Being cash collected recorded)

Interest revenue = Principal × rate of interest × number of months ÷ (total number of months in a year)

= $450,000 × 12% × (3 months ÷ 12 months)

= $13,500

The 3 months is calculated from December 31 to April 1

6 0

3 years ago